Answer:
The sum is a binomial with a degree of 6
Step-by-step explanation:
we have
(3x^{2}y^{2}-2xy^{5})+(-3x^{2}y^{2}+3x^{4}y)
Group terms that contain the same variable
(3x^{2}y^{2}-3x^{2}y^{2})-2xy^{5}+3x^{4}y
0-2xy^{5}+3x^{4}y
-2xy^{5}+3x^{4}y
The sum is a binomial ( two terms) with a degree of 6
-2xy^{5} has a degree of 6 (x has an exponent of 1, y has 5, and 1+5=6)
Answer:
look this for the solution
The age of citizens allowed to vote is x:
x >= 18
B
the age of citizens allowed to vote, x, is all the line number from 18 to the right, than is x equal or greater than 18
From the given dimensions, of MI, IN, NT, TM, and MN, the quadrilateral
MINT can be drawn as shown in the attached image.
<h3>What are the steps for the construction of MINT?</h3>
The given dimensions of the quadrilateral MINT are;
MI = 5 cm
IN = 6 cm
NT = 7 cm
TM = 3 cm
MN = 9 cm
The side MN is a diagonal of MINT, therefore;
ΔMIN, and ΔMTN are triangles with a common base = MN
The steps to construct MINT are therefore;
- Step 1; Draw the line MN = 9 cm.
- Step 2; Place the compass at point <em>M</em> and with a radius MI = 5 cm, draw an arc on one side of MN.
- Step 3; Place the compass at <em>N</em> and with radius IN = 6 cm, draw an arc to intersect the arc dawn in step 1 above.
- Step 4; Place an arc at point <em>M</em> and with radius TM = 3 cm draw an arc on the other side of MN.
- Step 5; Place the compass at point <em>N</em> and with radius NT = 7 cm, draw an arc to intersect the arc drawn in step 3.
- Step 6; Join the point of intersection of the arcs to points <em>M</em> and <em>N</em> to complete the quadrilateral MINT.
Please find attached the drawing (showing the construction arcs) of the
quadrilateral MINT created with MS Word.
Learn more about types of geometric construction here:
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I belive the 3rd picture is A so sorry if i get this wrong