The function is definately defined at x=0 but not x=1.
But its just one part of the coordinate (x,y).
If the value of y or f(x) is considered, you'll see that it is never possible to attain f(x)=0. In other terms (x,y)= (0,0) is not a defined point in the graph of the function because the graph doesnt pass through that point.
Now I hope you understood what I meant!
Conclusion- The above function is not defined at all points in the space having the abscissa or x=1 in the coordinate and also at ordinate or y=0 in the coordinate.nation:
Answer:
(-8,-4) and (-2,5). at reflect on x axis
Answer:
Step-by-step explanation:
Hint: 1 - Cos² A = Sin² A
Answer:
<em>13.1</em>
Step-by-step explanation:
A = bh
~~~~~~~
= 16 , 
= 9
A = 16 × 9 = 144
From another side area of parallelogram with hight "h" base "b"
11h = 144
<em>h</em> = 144 ÷ 11 ≈ <em>13.1</em>
