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svlad2 [7]
3 years ago
9

How do I solve 5/9x + 1/6 = -3/4

Mathematics
2 answers:
joja [24]3 years ago
6 0
Hope this helps but I think the answer is -33/20 which simplifies to -1  13/20
Anika [276]3 years ago
6 0
First convert 5/9 into 20/36, 1/6 into 6/36, -3/4 into -27/36
Now the math

20/36x + 6/36 = -27/36
- 6/36. - 6/36
20/36x = -33/36
/(20/36) /(20/36)
x = -33/20 or -1.65
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4750 dollars

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Step-by-step explanation:

To calculate the midpoint, you need to plug in the values of x and y into the midpoint formula.

M ( x1 + x2/2 , y1 + y2/2)

M [ -8 + 4/2 , -7 + 9/2]

M ( -2, 1)  

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A group of women tried five brands of fingernail polish and ranked them according to preference. What level of measurement is th
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5 0
3 years ago
Assume that we have two events, and , that are mutually exclusive. Assume further that we know and . If an amount is zero, enter
sweet [91]

Answer:

Explained below.

Step-by-step explanation:

The complete question is:

Assume that we have two events, A and B, that are mutually exclusive. Assume further that we know P(A) = 0.30 and P(B) =0.40.

What is P(A and B)?

What is P(A | B)?

Is P(A | B) equal to P(A)?

Are events A and B dependent or independent?

A student in statistics argues that the concepts of mutually exclusive events and independent events are really the same, and that if events are mutually exclusive they must be independent. Is this statement accurate?

What general conclusion would you make about mutually exclusive and independent events given the results of this problem?

Solution:

The probability of the two events <em>A</em> and <em>B</em> are:

P(A) = 0.30 and P(B) =0.40

(a)

Compute the value of P (A ∩ B) as follows:

P(A\cap B)=0

This is because mutually exclusive events are those events that cannot occur together.

(b)

Compute the value of P (A | B) as follows:

P(A|B)=\frac{P(A\cap B)}{P(B)}=\frac{0}{0.40}=0

Thus, the value of P (A | B) is 0.

(c)

No, P (A | B) is not equal to the P (A).

(d)

As mentioned in part (a), mutually exclusive events are those events which cannot occur together.

That is, P(A\cap B)=0.

Events A and B are independent  if the chance of their concurrent happening is equivalent to the multiplication of their distinct probabilities.

That is, P(A\cap B)=P(A)\times P(B).

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(e)

As the it is provided that A and B are mutually exclusive events, we know that P(A\cap B)=0.

Now compute the value of P(A)\times P(B) as follows:

               P(A)\times P(B)=0.30\times 0.40=0.12\neq 0

Thus, the events A and B are not independent.

Thus, if two events are mutually exclusive events they cannot be independent.

4 0
3 years ago
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Answer: She needed 1\frac{1}{2}\text{ pounds of blueberries} to make a cup of jam .

Step-by-step explanation:

Since we have given that

Sarah used \frac{3}{4} pound of blueberries to make \frac{1}{2} cup of jam.

As we need to find the number of pounds of blueberries she would need to make a cup of jam.

So, we will use "Unitary Method":

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Hence, She needed 1\frac{1}{2}\text{ pounds of blueberries} to make a cup of jam .

4 0
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