Question

A game is played with a played pentagonal spinner with sides marked 1 to 5. The scorer is on the side which comes to rest on the table. In two spins what is the probability of getting two 5s, at least one 5, a total score of 5, a total score greater than 5.

Answer 1

Answer: probability of getting two 5s =0.04

probability of getting at least one 5 =0.36

probability of getting a total score greater than 5 =0.6

Step-by-step explanation:

Total outcomes on 1 spinner = 5

Then , total outcomes of spinning it 2 times=  $5\times5 = 25$

Number of outcomes for getting two 5's = 1

Then, the probability of getting two 5s $=\dfrac{\text{Favorable outcomes of getting two 5's }}{\text{Total outcomes}}$

$=\dfrac{1}{25}=0.04$

Number of outcomes for getting at least one 5 [ {(1,5),(2,5),(3,5),(4,5),(5,5), (5,1), (5,2), (5,3), (5,4)} ] =9

Then, the probability of getting at least one 5$=\dfrac{\text{Favorable outcomes of getting at least one 5 }}{\text{Total outcomes}}$

$=\dfrac{9}{25}=0.36$

Number of outcomes for getting a total score of 5, [ {(1,4),(4,1),(2,3),(3,2)} ] =4

Then, the probability of getting a total score of 5,$=\dfrac{\text{Favorable outcomes of getting a total score of 5 }}{\text{Total outcomes}}$

$=\dfrac{4}{25}$

Number of outcomes for getting a total score greater than 5 [ {(1,5),(5,1),(2,4),(4,2),(2,5), (5,2), (3,4),(4,3), (3,5), (5,3), (3,3), (4,5), (5,4), (4,4), (5,5)} ] =15

Then, the probability of getting a total score greater than 5,$=\dfrac{\text{Favorable outcomes of getting a total score greater than 5 }}{\text{Total outcomes}}$

$=\dfrac{15}{25}=\dfrac{3}{5}=0.6$