Question

EEF has vertices D(1, 3), E(2, -4), and F(-3, 1). What are the vertices T<4, 1> (DEF).

Answer 1

The vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)

How to determine the vertices?

The vertices of the triangle are given as:

D(1, 3), E(2, -4), and F(-3, 1).

The transformation represented by T<4, 1> (DEF) is:

(x,y) = (x + 4, y + 1)

So, we have;

D' = (1 + 4, 3 + 1)

D' = (5, 4)

E' = (2 + 4, -4 + 1)

E' = (6, -3)

F' = (-3 + 4, 1 + 1)

F' = (1, 2)

Hence, the vertices T<4, 1> (DEF) are D' = (5, 4), E' = (6, -3) and F' = (1, 2)

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