Answer:
Not possible
Step-by-step explanation:
The notation (f °g)(-2) means f(g(-2)). You will substitute -2 into g(x) then substitute the value or equation that results into f(x).
g(-2) = √x - 16 = √-2 - 16
This is not possible because the value of -2 cannot be found in a square root. Square roots do not compute real roots for negative numbers.
Answer:
t0 = π/4
Step-by-step explanation:
The velocity v(t) = r'(t) = <-2sint,-2cost>
Since <1,-1>⊥v, <1,-1>•v=0. So,
(1)(-2sint) + (-1)(-2cost) = 0
cost - sint = 0
Answer:
x = -2
Step-by-step explanation:
![f(x) =x^2 -2x\:\: and \:\: g(x) = 6x + 4\\(f+g)(x) = f(x) + g(x) \\(f+g)(x) = x^2 -2x+ 6x + 4\\(f+g)(x) = x^2+4x + 4\\(f+g)(x) = (x+2)^2\\ 0 = (x+2)^2...[\because (f+g)(x) =0]\\0 = x+2\\\therefore x = -2](https://tex.z-dn.net/?f=f%28x%29%20%3Dx%5E2%20-2x%5C%3A%5C%3A%20and%20%5C%3A%5C%3A%20g%28x%29%20%3D%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20f%28x%29%20%2B%20g%28x%29%20%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%20-2x%2B%206x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20x%5E2%2B4x%20%2B%204%5C%5C%28f%2Bg%29%28x%29%20%3D%20%28x%2B2%29%5E2%5C%5C%200%20%3D%20%28x%2B2%29%5E2...%5B%5Cbecause%20%28f%2Bg%29%28x%29%20%3D0%5D%5C%5C0%20%3D%20x%2B2%5C%5C%5Ctherefore%20x%20%3D%20-2)
Answer:
C and F
Step-by-step explanation:
23/40 can't be simplified as it has no common factors
