Step 1:
First, find the total number of students.
Let the total number of students = m
Step 2:
Find the total number of students using the percentage of 4 books.
48 students listed 4 books with a percentage of 16%

Hence, there are 300 students.
a)

72 students had 1 book.
b) What percentage more read 2 books than 4 books?
percentage that read 2 books = 36%
percentage that read 4 books = 16%
36 - 16 = 20%
There are 20% students that read 2 books than 4 books.
Using the z-distribution, it is found that the 90% confidence interval is given by: (0.6350, 0.6984).
<h3>What is a confidence interval of proportions?</h3>
A confidence interval of proportions is given by:

In which:
is the sample proportion.
In this problem, we have a 90% confidence level, hence
, z is the value of Z that has a p-value of
, so the critical value is z = 1.645.
The sample size and the estimate are given by:

Hence, the bounds of the interval are given by:


The 90% confidence interval is given by: (0.6350, 0.6984).
More can be learned about the z-distribution at brainly.com/question/25890103
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Answer:
(5x-1)^2=16
Step-by-step explanation:
Give me the points thanks
5 least common multiple is 5 nines is 3 and thirty's is 3