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Komok [63]
2 years ago
12

The dimension of a mural pointed on the wall of a school is 10 ft by 22 ft. the art club wants to paint a new mural that is x fe

et longer and x feet wider. Find the new dimensions of the new mural with an area of 540 square feet
Mathematics
1 answer:
Westkost [7]2 years ago
6 0

Answer:

  • 18 ft and 30 ft

Step-by-step explanation:

<u>The new dimensions will be:</u>

  • 10 + x and 22 + x

The area is 540

<u>Using area equation we get:</u>

  • (10 + x)(22 + x) = 540
  • x² + 32x + 220 = 540
  • x² + 32x = 320
  • x² + 2x*16 + 256 = 320 + 256
  • (x + 16)² = 576
  • x + 16 = √576  (Ignoring the negative root as the length is never negative)
  • x + 16 = 24
  • x = 8

<u>The new dimensions are:</u>

  • 10 + 8 = 18 ft and
  • 22 + 8 = 30 ft
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Step 1

Given;

\begin{gathered} \text{Principal(p)= \$375000} \\ \text{First rate = 8\%=}\frac{8}{100}=0.08 \\ \text{Second rate = 20\%= }\frac{20}{100}=0.2 \\ \text{Time}=\frac{90}{365}=\frac{18}{73} \end{gathered}

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Step 2

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Step 3

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\begin{gathered} A=375000(1+(0.08\times\frac{18}{73}) \\ A=375000(1+\frac{36}{1825}) \\ A=\text{\$}382397.26 \end{gathered}

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\begin{gathered} A=375000(1+(0.2\times\frac{18}{73}) \\ A=\text{\$}393493.15 \end{gathered}

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A-p=393493.15-375000=\text{\$}18493.15\text{ }

Step 5

Find the difference in interest between the two rates.

\text{\$}18493.15-\text{\$}7397.26=\text{\$}11095.89

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