It’s the first one otherwise known as a
Answer:
(a) and (a)
Step-by-step explanation:
In both questions the denominator of the rational functions cannot be zero as this would make them undefined. Equating the denominators to zero and solving gives the values that x cannot be.
Given

solve (3 - x)(2 + x) = 0
Equate each factor to zero and solve for x
3 - x = 0 ⇒ x = 3
2 + x = 0 ⇒ x = - 2
x = 3 and x = - 2 are excluded values → (a)
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Given

solve
6x² + 10x - 4 = 0 ← in standard form
(x+ 2)(6x - 2) = 0 ← in factored form
Equate each factor to zero and solve for x
x + 2 = 0 ⇒ x = - 2
6x - 2 = 0 ⇒ 6x = 2 ⇒ x = 
x =
and x = - 2 are excluded values → (a)
The next number is 17.
The sequence adds by 2 everytime.
<h2>
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<em><u>Y</u></em><em><u>e</u></em><em><u>s</u></em><em><u>.</u></em><em><u> </u></em><em><u>balancing an unknown mass against a known mass.</u></em>
<h2>
<em><u>E</u></em><em><u>x</u></em><em><u>p</u></em><em><u>l</u></em><em><u>a</u></em><em><u>n</u></em><em><u>a</u></em><em><u>t</u></em><em><u>i</u></em><em><u>o</u></em><em><u>n</u></em><em><u>:</u></em></h2>
Hope it helps
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