Given a square ABCD and an equilateral triangle
DPC and given a chart with which
Jim is using to prove that triangle APD is
congruent to triangle BPC.
From the chart, it can be seen that Jim proved that two corresponding sides of both triangles are congruent and that the angle between those two sides for both triangles are also congruent.
Therefore, the justification to complete Jim's proof is "SAS postulate".
Answer:
83/100
Step-by-step explanation:
Answer:
x = 34 degrees
Step-by-step explanation:
if this is a parallelogram then Δ ACB ≅ Δ DCB
which means that ∠A = ∠D
Add 1 to both sides:
In cases like this, we have to remember that a root is always positive, so we can square both sides only assuming that
Under this assumption, we square both sides and we have
The solutions to this equation are
But since we can only accept solutions greater than -1, we discard 
and accept 
.
In fact, we have
and
which is the only solution.
N=5 or n=9 can be either one
Hope this helped
