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a_sh-v [17]
3 years ago
10

Order the following rational numbersfrom greatest to least. 7.5, -6, 7/8, -8/7​

Mathematics
2 answers:
lukranit [14]3 years ago
8 0

Answer:

-6, -8/7, 7/8, 7.5

Step-by-step explanation:

.................

Bess [88]3 years ago
6 0

Answer: -6, -8/7, 7/8, 7.5

Step-by-step explanation: To compare them, you need to make sure they are all either fractions or decimals. -6 = -6 .... -8/7 = -1 1/7 ...... 7/8 = 7/8 ..... and 7.5 = 7 1/2

-6, -1 1/7, 7/8, and 7 1/2

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Translate the following word phrase into an algebraic expression: nine times five less than twice x.
bagirrra123 [75]

The given statement is "nine times five less than twice x".

So, twice of x can be written as 2x and nine times five is 9*5.

Now 9*5 less 2x means we need to take out 9*5 from 2x.

Hence, this statement will be converted into an algebraic expression as follows:

2x-9*5

4 0
3 years ago
One stats class consists of 52 women and 28 men. Assume the average exam score on Exam 1 was 74 (σ = 10.43; assume the whole cla
Svetllana [295]

Answer:

(A) What is the z- score of the sample mean?

The z- score of the sample mean is 0.0959

(B) Is this sample significantly different from the population?

No; at 0.05 alpha level (95% confidence) and (n-1 =79) degrees of freedom, the sample mean is NOT significantly different from the population mean.

Step -by- step explanation:

(A) To find the z- score of the sample mean,

X = 75 which is the raw score

¶ = 74 which is the population mean

S. D. = 10.43 which is the population standard deviation of/from the mean

Z = [X-¶] ÷ S. D.

Z = [75-74] ÷ 10.43 = 0.0959

Hence, the sample raw score of 75 is only 0.0959 standard deviations from the population mean. [This is close to the population mean value].

(B) To test for whether this sample is significantly different from the population, use the One Sample T- test. This parametric test compares the sample mean to the given population mean.

The estimated standard error of the mean is s/√n

S. E. = 16/√80 = 16/8.94 = 1.789

The Absolute (Calculated) t value is now: [75-74] ÷ 1.789 = 1 ÷ 1.789 = 0.559

Setting up the hypotheses,

Null hypothesis: Sample is not significantly different from population

Alternative hypothesis: Sample is significantly different from population

Having gotten T- cal, T- tab is found thus:

The Critical (Table) t value is found using

- a specific alpha or confidence level

- (n - 1) degrees of freedom; where n is the total number of observations or items in the population

- the standard t- distribution table

Alpha level = 0.05

1 - (0.05 ÷ 2) = 0.975

Checking the column of 0.975 on the t table and tracing it down to the row with 79 degrees of freedom;

The critical t value is 1.990

Since T- cal < T- tab (0.559 < 1.990), refute the alternative hypothesis and accept the null hypothesis.

Hence, with 95% confidence, it is derived that the sample is not significantly different from the population.

6 0
3 years ago
Can someone explained what i am supposed to do in this picture.
FinnZ [79.3K]
Well i think you are suppose to explain how OR WHAT THE CHANGE IN DECREASE Is.
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7 0
3 years ago
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Please help, correct answer gets brainiest incorrect/trolling is reported.
ioda

Answer:

5

Step-by-step explanation:

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6 0
3 years ago
Read 2 more answers
What are the rate of changes for
astraxan [27]
<span>39 & 16.5 = -22.5
30 & 12.4 = -17.6
28 & 10.4 = -17.6
19 & 10.3 = -8.7
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</span>
3 0
3 years ago
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