It =11 not how is it 10 what did you think it was
Answer:
![y = \frac{1}{2}x - 6](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-%206)
Step-by-step explanation:
Slope of line (m) = 1/2
Since the line is passing through the point (6, -3) ∴ ![x_{1} = 6\ and\ y_{1} = -3](https://tex.z-dn.net/?f=x_%7B1%7D%20%3D%206%5C%20and%5C%20y_%7B1%7D%20%3D%20-3)
Now, equation of line in Point-slope form is:
![(y - y_{1}) = m (x - x_{1})](https://tex.z-dn.net/?f=%28y%20-%20y_%7B1%7D%29%20%3D%20m%20%28x%20-%20x_%7B1%7D%29)
By substituting the values of m,
![(y - (3)) = \frac{1}{2}(x - 6)](https://tex.z-dn.net/?f=%28y%20-%20%283%29%29%20%3D%20%5Cfrac%7B1%7D%7B2%7D%28x%20-%206%29)
![y + 3 = \frac{1}{2} ( x - 6)](https://tex.z-dn.net/?f=y%20%2B%203%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20%28%20x%20-%206%29)
![y = \frac{1}{2}x - 3 - 3](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-%203%20-%203)
![y = \frac{1}{2}x - 6](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-%206)
Therefore, the equation of line passing through pong (6, -3) is ![y = \frac{1}{2}x - 6](https://tex.z-dn.net/?f=y%20%3D%20%5Cfrac%7B1%7D%7B2%7Dx%20-%206)
x = 8, --- 12
I hope this helped :))))))))))))))))))
Answer:
Infinite solutions
Step-by-step explanation:
3(2d-1)-2d=4(d-2)+5 | Given equation
6d - 3 - 2d = 4d - 8 + 5 | Distribute
4d - 3 = 4d - 3 | Combine like-terms
4d = 4d
Infinite solutions, the terms are equal.