If a polynomial function f(x) has roots 0, 4, and 3+ /11, what must also be a root of f(x)?

Mathematics

1 answer:

seropon [69]3 years ago

6 0

Answer:

3 - $\sqrt{11}$

Step-by-step explanation:

Assuming the root given is 3 + $\sqrt{11}$

Radical roots occur in conjugate pairs, thus

if 3 + $\sqrt{11}$ is a root , then 3 - $\sqrt{11}$ is also a root

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Read 2 more answers

Write 6.7 in two other forms

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