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ladessa [460]
4 years ago
7

How will adding the value 8 affect the mean and median of the data set 4, 6, 8, 10, 12?

Mathematics
2 answers:
prisoha [69]4 years ago
4 0

Answer:

Option: D is the correct answer.

Both mean and median stay the same.

Step-by-step explanation:

  • We are given a data set as:

4, 6, 8, 10, 12

Clearly from the data set we could see that the median of the set is:

Median=8

( Since we know that the median of the set is the central tendency of a data and always exist in the middle of the data set)

Also, we have 5 data points hence, the mean is calculated as:

Mean=\dfrac{4+6+8+10+12}{5}\\\\\\Mean=\dfrac{40}{5}\\\\Mean=8

Hence, we have:

Mean=8

and Median=8

  • Now when we add another point 8 to the set we have the set in increasing order as:

4,6,8,8,10,12

Hence, now the median lies between 8 and 8.

Hence, we get Median=8

( Since, (8+8)/2=16/2=8)

Also, Mean is calculated as:

Mean=\dfrac{4+6+8+8+10+12}{6}\\\\Mean=\dfrac{48}{6}\\\\Mean=8

Hence, we have:

Mean=8

and Median=8

So, the statement that can be inferred form the addition of a new data point is:

D.

The mean and median will both stay the same.

zloy xaker [14]4 years ago
3 0
4, 6, 8, 10, 12

Mean without 8:

Mean is adding all the numbers and dividing by how many numbers there are.

4 + 6 + 8 + 10 + 12 = 40

40 / 5 = 8

So the mean is 8.

Mean with 8:

4, 6, 8, 8, 10, 12

4 + 6 + 8 + 8 + 10 + 12 = 48

48 / 6 = 8

So the mean is 8.

Median without 8:

4, 6, 8, 10, 12

Median is the middle number. In this case it's 8.

Median with 8:

4, 6, 8, 8, 10, 12

Median is the middle number, there are two 8's in the middle, so the median is 8.

Therefore the mean and the median both stay the same.
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MrBillDoesMath!


Answer to #4:  81/256 * s^8 * t^ 12


Comments:

(7x^3) ^ (1/2)   =  7 ^ (1/2)  *  x^(3/2)   where  ^(1/2) means the square root of a quantity. The answer written (7x^3) is NOT correct.

---------------------

(1)             (27s^7t^11)^ (4/3)  

               = 27^(4/3) * (s^7)^(4/3) * (t^11)^ (4/3)


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(2)  (-64st^2)^ (4/3)  =     (-64)^(4/3) * (s^4/3) * t(^8/3)


As 64 = (-4)^3,  (-64)^(4/3) = (-4)^4 = +256                                        


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-------------------------------     =

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