4/11 and 6/7 is already in simplest form
Answer:
1003
Step-by-step explanation:
The problem is a classic example of a telescoping series of products, a series in which each term is represented in a certain form such that the multiplication of most of the terms results in a massive cancelation of subsequent terms within the numerators and denominators of the series.
The simplest form of a telescoping product
, in which the products of <em>n</em> terms is
.
In this particular case,
,
,
, ..... , in which each term follows a recursive formula of
. Therefore,

A/7 + 5/7 = 2/7
1/7a + 5/7 = 2/7
1/7a + 5/7 - 5/7 = 2/7 - 5/7
1/7a = -3/7
7*(1/7a) = 7*(-3/7)
a = -3
Answer:
assuming 2y - 4x equals 0 the answer is no solution
Step-by-step explanation:
2(2x-5) - 4x = 0
4x-10 -4x=0
combine like terms
-10=0
no solution
Answer:
40
Step-by-step explanation:
s = 2;
h = 4
Surface area = 2s² + 4sh
= 2*2² + 4 * 2 * 4
= 2 *4 + 32
= 8 + 32
= 40 sq. units