All categories

3 years ago

I need all I don't know how to do????

Mathematics

1 answer:

Ghella [55]3 years ago

6 0

Need the answers to all the questions?

You might be interested in

1 hundredth + 3 tenth

kakasveta [241]

Answer:

Look at the attachment

4 0

2 years ago

Read 2 more answers

What is 3√125x^12 A) 5x^2 B) 5x^4 C) 25x^2 D) 25x^4

Schach [20]

$\sqrt[3]{125x^{12}}=\sqrt[3]{125}\cdot\sqrt[3]{x^{4\cdot3}}=5\sqrt[3]{(x^4)^3}=5x^4\\\\\text{Answer:}\ B)\ 5x^4\\\\\text{Used:}\\\sqrt[n]{a\cdot b}=\sqrt[n]{a}\cdot\sqrt[n]{b}\\\\(a^n)^m=a^{n\cdot m}\\\\\sqrt[n]{a^n}=a$

5 0

3 years ago

Read 2 more answers

What does x equal in x^3-9x+1=0

12345 [234]

X^3 -9x+1= 0 (minus 1)

X^3-9x=-1 (divide by 9)

x^3-x=-1/9

But it doesn’t work any further so you have written it wrong

5 0

2 years ago

What is the value of x in the diagram?

cestrela7 [59]

Answer:

x = 5

Step-by-step explanation:

x² + (2x+2)² = (2x+3)²

x² + 4x² + 8x + 4 = 4x² + 12x + 9

x² - 4x - 5 = 0

(x - 5)(x + 1) = 0

x = -1 This can be discounted as the answer because you cannot have a negative length

answer: x = 5

5 0

2 years ago

0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?

MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So, 4# · 3# · 2# · 1#? = 6912 · 24 · 2 · 1? = 331776

7 0

2 years ago