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iogann1982 [59]
3 years ago
12

3х'2 - 8x - 3

Mathematics
1 answer:
Tems11 [23]3 years ago
4 0

Answer:

3x+1/2x

Step-by-step explanation:

When simplifying algebraic expressions, we should first factorise each term fully to find any common factors. First we should factorise the numerator where 3x2-8x-3 factorises to (3x+1)(x-3). Next, we should factorise the denominator where 2x2-6x factorises to 2x(x-3). Now we see that (x-3) is the highest common factor of both the numerator and denominator, hence we can "cancel" the (x-3) term from both the numerator and denominator. Therefore, the expression simplifies fully to (3x+1)/(2x)

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5+ =83 can someone help me out
enot [183]
You can do
83 - 5 to find the answer
So that's
78 or
5 + 78 = 83
4 0
3 years ago
Read 2 more answers
Men are believed to have a slightly longer average length of short hospital stays than women; 5.2 days versus 4.5 days respectiv
Georgia [21]

Answer:

Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of singificance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

Step-by-step explanation:

1) Data given and notation  

\bar X_{1}=5.2 represent the mean for group men  

\bar X_{2}=4.5 represent the mean for group women  

Assuming these values for the remaining data:

\sigma_{1}=1.2 represent the population standard deviation for the sample men

\sigma_{2}=1.5 represent the population standard deviation for the sample women

n_{1}=32 sample size for the group men  

n_{2}=30 sample size for the group women  

z would represent the statistic (variable of interest)

p_v represent the p value  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to check if the mean for men it's higher than the mean for women, the system of hypothesis would be:  

H0:\mu_{1} \leq \mu_{2}  

H1:\mu_{1} > \mu_{2}  

If we analyze the size for the samples both are higher than 30, and we know the population deviation's, so for this case is better apply a z test to compare means, and the statistic is given by:  

z=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}} (1)  

z-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.  

3) Calculate the statistic  

We have all in order to replace in formula (1) like this:  

z=\frac{5.2-4.5}{\sqrt{\frac{1.2^2}{32}+\frac{1.5^2}{30}}}=2.02  

4) Find the critical value

In order to find the critical value we need to take in count that we are conducting a right tailed test, so we are looking on the normal standard distribution a value that accumulats 0.01 of the area on the right and 0.99 of the area on the left. We can us excel or a table to find it, for example the code in Excel is:

"=NORM.INV(1-0.01,0,1)", and we got z_{critical}=2.33

5) Statistical decision

Since our calculated value is lower than our critical value,z_{calc}=2.02, we have enough evidence to FAIL to reject the null hypothesis at 1% of significance. So there is not nough evidence to conclude that mean for men it's significantly higher than the mean for female.

6 0
3 years ago
A community is planning to build a rectangular garden.the width of the garden is 27/4 feet and the perimeter of the garden is 37
Crank

We know that the width of the garden is = \frac{27}{4} feet = 6.75 feet

and Perimeter of the garden is = 37.5 feet

Also, we know that for a rectangular space perimeter = 2 * (l + w)

⇒ 37.5 = 2 * (l + 6.75)

⇒ 37.5 = 13.5 + 2*l

⇒ 24 = 2*l

⇒ l = 12 feet

Now, we need to determine how much square feet of mulch is required, hence we need to calculate the area of the garden

Area = l * w

⇒ Area = 12 * 6.75

⇒ Area = 81 square feet

Hence, they require 81 square feet of mulch

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belka [17]

Answer:b

Step-by-step explanation:

7 0
2 years ago
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X-y=8 is the answer to 8+y=x
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