ANSWER
Find out the how many pounds of nickel have to be used to create alloy that contains 4.9 lb of zinc.
To proof
As given
An alloy consists of nickel, zinc, and copper in the ratio 2:7:9.
the total part of the alloy are 18.
assuming one part be x.
thus
nickel part = 2x
zinc part = 7x
copper part = 9x
alloy that contains 4.9 lb of zinc.
than the equation becomes
7x = 4.9

x = 0.7
Therefore
nickel part = 2x
= 2× 0.7
= 1.4 lb
1.4 lb of nickel have to be used to create alloy that contains 4.9 lb of zinc.
Hence proved
Answer:
x = 50°
y = 50°
z = 80°
Step-by-step explanation:
working out x:
angles on a straight line add up to 180°
x + 130° = 180°
subtract 130 on both sides
x = 180° - 130°
x = 50°
working out y:
two vertical lines means that both sides are equal, so both angles are also equal (it's an isosceles triangle). This means that y is the same angle as x = 50°
y = 50°
working out z:
the sum of a triangle add up to 180°
add up the angles of x and y and equate to 180°
50 + 50 + z = 180
100 + z = 180
subtract 100 on both sides
z = 180 - 100
z = 80°
Answer:
I would say c because if you have -2-(-4) you really have -2 + 4 so it would be a positive 2 instead of -2
Answer:
2*2*9+4*12*3=36+144=180
Step-by-step explanation: