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bija089 [108]
3 years ago
10

A company logo is made up of a square and three identical triangles.

Mathematics
1 answer:
aniked [119]3 years ago
6 0

Answer:

give me a minute to find the answer.

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PLEASE HELP!!!! I NEED TO DO THIS IN ANOTHER SHARP TEN MINUTES!! PLEASE!! I BEG YOU PEOPLE!!
Pavlova-9 [17]
60*80/100-$10*155/100
48-$10*155/100=$58.90

6 0
3 years ago
A triangle on a coordinate plane is translated according to the rule 6, 4(x,y). Which is another way to write this rule?
Mashcka [7]

Answer:

C

Step-by-step explanation:

5 0
3 years ago
A family pays $45 each month for cable television. the cost increases 7%.a. how many dollars is the increase?the increase is $.b
yKpoI14uk [10]
It increased by $3.15
The new monthly cost is $48.15
3 0
3 years ago
18+6/-4-16 HELP only d part​
Ivahew [28]

Answer:

\frac{1}{2} is the answer

Step-by-step explanation:

First we need to substitute X and Y with their respective numbers

3\cdot \:6+\frac{6}{-4}-\left(-4\right)^2

Then, following PEMDAS, We just need to simplify

18+\frac{6}{-4} -16

16.5-16=0.5=\frac{1}{2}

3 0
2 years ago
Read 2 more answers
A certain car rental location charges a daily fee as well as a mileage charge. On one trip a businessman rented a car for the da
nikklg [1K]

Answer:

x\approx 267\ miles

Step-by-step explanation:

<u>Linear Modeling</u>

Some events can be modeled as linear functions. If we are in a situation where a linear model is suitable, then we need two sample points to make the model and predict unknown behaviors.

The linear function can be expressed in the slope-intercept format:

f(x)=mx+b

For the problem at hand, we must pick the adequate variables according to the data provided.

The question states the charge for renting a car is a function of the mileage. It also provides two points from which we can build our model. Let's set the following variables:

c = the charge for renting a car in dollars

x = the distance driven by the businessman in miles

Representing the ordered pair as (x,c), we have the points: (150,79) and (65,63.70). Our model will be expressed as:

c = mx+b

We must find the values of m and b with the data provided. Substituting the first point:

79 = 150m+b

Substituting the second point:

63.70 = 65m+b

Both equations form the following system:

\left\{\begin{matrix}150m+b=79\\ 65m+b=63.70 \end{matrix}\right.

Subtracting both equations:

150m-65m=79-63.70

Note the variable b was canceled out in the operation, leaving only the variable m to solve. Joining like terms:

85m=15.3

Solving:

m=15.3/85=0.18

From the first equation

79 = 150m+b

Solving for b:

b=79-150m=79-150(0.18) = 52.

The model for the problem is:

c=0.18x+52

Now we need to calculate how many miles (x) could be driven for c=$100. From the equation above, substitute c=100

100=0.18x+52

Solve for x:

0.18x+52=100

0.18x=100-52=48

x=48/0.18=266.67

Rounding to the closest integer:

\boxed{x\approx 267\ miles}

7 0
3 years ago
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