Answer:
x=2
Step-by-step explanation:
8 + x = 4x +2
Subtract 4x from both sides:
8 + x - 4x = 4x + 2 - 4x
Group like terms:
x - 4x + 8 = 4x + 2 -4x
Simplify the arithmetic:
-3x + 8 = 4x + 2 -4x
Group like terms:
-3 + 8 = 4x - 4x + 2
Simplify the arithmetic:
-3x + 8 = 2
The measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
<h3>what is measure centre and measure of variation? </h3>
A measure of central tendency (measure of centre) is a value that attempts to describe a set of data by identifying the central position of the data set.
The measure of central tendency includes the mean, median and mode.
The measure of variation describes the amount of variability or spread in a set of data.
The common measures of variability are the range, the interquartile range (IQR), variance, and standard deviation.
Therefore, the measure of centre includes mean median and mode and the measure of variability includes range, interquartile range and mean absolute deviation.
learn more on measure of centre and variation here: brainly.com/question/23769503
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Answer:
0.35% of students from this school earn scores that satisfy the admission requirement.
Step-by-step explanation:
Normal Probability Distribution:
Problems of normal distributions can be solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
The combined SAT scores for the students at a local high school are normally distributed with a mean of 1479 and a standard deviation of 302.
This means that 
The local college includes a minimum score of 2294 in its admission requirements. What percentage of students from this school earn scores that satisfy the admission requirement?
The proportion is 1 subtracted by the pvalue of Z when X = 2294. So



has a pvalue of 0.9965
1 - 0.9965 = 0.0035
0.0035*100% = 0.35%
0.35% of students from this school earn scores that satisfy the admission requirement.
Acute is a angle of some sort I believe.
11°F is what the temperature was at 5:00 a.m.