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hram777 [196]
3 years ago
11

Drag a statement or reason to each box to complete this proof

Mathematics
1 answer:
evablogger [386]3 years ago
7 0

Answer:

1. E

2. D, C

4. B

Step-by-step explanation:

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Hello! Can someone please help me with these 2 questions! thank you so much! (i’ll give brainlist)
ra1l [238]

Answer:

1) 4    2)1/5   X=10

Step-by-step explanation:

Small to large is a fraction

Large to small is a whole number

3 0
3 years ago
Here is an expression.
Zielflug [23.3K]

Answer:

sorry..

Step-by-step explanation:

1

A student made 6 bows from 12 yards of ribbon. How many bows can be made from 3

2

yards of ribbon?

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D A bag of almonds weighs 1-pounds.

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3 years ago
What is the ratio of 50 and 10
Lubov Fominskaja [6]

Answer:

5:1

Step-by-step explanation:

10 the greatest common factor.

50 divided by 10 is 5

10 divided by 10 is one

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8 0
4 years ago
Read 2 more answers
Helppp - find the area of each figure & round to the nearest tenth
Karo-lina-s [1.5K]

Answer:

112 ft

Step-by-step explanation:

9) Here, we are finding the area of a triangle. The equation for area is:

A = \frac{1}{2} *b*h

Where A is area, b is the base, and h is height.

A = \frac{1}{2} * 16 * 14

A = 112

5 0
2 years ago
A recent kellogg survey shows that approximately 34% of americans eat breakfast. suppose alex takes a random sample of four amer
vlabodo [156]

This kind of experiments are ruled by Bernoulli's formula. If you have probability p of "success", and you want k successes in n trials, the probability is


\binom{n}{k}p^k(1-p)^{n-k}


It's easier to compute the first probability by difference: instead of computing the probability of the event "at least one of the surveyed eats breakfast", let's compute the probability of its contrary: none of them eats breakfast. So, we want 0 successes in 4 trials, with probability of success 0.34. The formula yields


\binom{4}{0} 0.34^0 0.64^4 = 0.64^4 \approx 0.17 = 17\%


Since the contrary has probability 17%, our event "at least one of the surveyed eats breakfast" has probability 83%.


As for the second question, the event "at least three of the surveyed eats breakfast" is the union of the events "exactly three of the surveyed eats breakfast" and "exactly four of the surveyed eats breakfast". So, we just need to sum their probabilities:


\binom{4}{3} 0.34^3 0.64^1 +\binom{4}{4} 0.34^4 0.64^0 = 4\cdot  0.34^3 0.64 + 0.34^4 \approx 0.11 = 11\%

3 0
3 years ago
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