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Nady [450]
3 years ago
7

What are the first five terms of the pattern with the formula 2n + 2?

Mathematics
1 answer:
alukav5142 [94]3 years ago
8 0
An = 2n + 2

a1 = 2(1) + 2 = 2 + 2 = 4
a2 = 2(2) + 2 = 4 + 2 = 6
a3 = 2(3) + 2 = 6 + 2 = 8
a4 = 2(4) + 2 = 8 + 2 = 10
a5 = 2(5) + 2 = 10 + 2 = 12
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A bike rental stand at the beach charges $5 to rent a bike in targit charges to every half hour it is rented if someone pays $17
denis23 [38]

Answer:

They would have the bike for 1.7 hours

Step-by-step explanation:

The bike is rented at a charge of $5 for every half an hour,this can be expressed as:

$5 per 0.5 hours, to calculate the time one will have the bike if they pay $17

The amount of paid=Standard Rate per 1/2 of an hour/Number of hours

where;

The amount paid=$17

Standard Rate per 1/2 an hour=$5/0.5

Number of hours

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5 0
3 years ago
A recent research show that only 40% of the customers are willing to pay more for the service. Now we have selected 10 customers
Strike441 [17]

Answer:

The expected number of customers that pay more for the service is 4 and the standard deviation is 1.55.

Step-by-step explanation:

For each customer, there are only two possible outcomes. Either they are willing to pay more for the service, or they are not. Customers are independent. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

40% of the customers are willing to pay more for the service.

This means that p = 0.4

Now we have selected 10 customers randomly.

This means that n = 10

What are the expected value and standard deviation

E(X) = np = 10*0.4 = 4

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{10*0.4*0.6} = 1.55

The expected number of customers that pay more for the service is 4 and the standard deviation is 1.55.

3 0
3 years ago
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4 0
3 years ago
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Hope I helped!

5 0
3 years ago
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