I assume (x-4)3 means (x-4)³. What we wish is to set the derivative equal to zero.
Expanding the T(x) polynomial makes it easier for me to take the derivative.
So (x-4)³ = x³ - 12x² + 48x - 64 + 6
T'(x) = 3x² - 24x + 48
We can factor out a 3 and set this to zero:
x² - 8x + 16 = 0
(x -4)² = 0
x = 4 should therefore represent the turning point.
I am mildly chagrined, I almost used the f'(x) = nx^(n-1) function at first, which appears would have been correct.
Answer:
x = 96
Step-by-step explanation:
x = 180 - (34 + 50)
x = 180 - 84
x = 96
<em>You are smart, remember that! You just have a little trouble with this problem, that's all! </em>
<em>Hope that helps!</em>
<em>-Sabrina</em>
Answer:
it is d i am 20 percent postive
Julie is corrected since 3×9=27 and you could still divide 27÷3 and have no remainders.
A liner graph shows the answer
