Combine like terms: Then solve
(-5a3 + 6a3) + (-2a2 +9a2) + 8a =
Part a.
The domain is the set of x values such that
, basically x can be equal to -1/2 or it can be larger than -1/2. To get this answer, you solve
for x (subtract 1 from both sides; then divide both sides by 2). I set 2x+1 larger or equal to 0 because we want to avoid the stuff under the square root to be negative.
If you want the domain in interval notation, then it would be
which means the interval starts at -1/2 (including -1/2) and then it stops at infinity. So technically it never stops and goes on forever to the right.
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Part b.
I'm going to use "sqrt" as shorthand for "square root"
f(x) = sqrt(2x+1)
f(10) = sqrt(2*10+1) ... every x replaced by 10
f(10) = sqrt(20+1)
f(10) = sqrt(21)
f(10) = 4.58257569 which is approximate
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Part c.
f(x) = sqrt(2x+1)
f(x) = sqrt(2(x)+1)
f(x+2a) = sqrt(2(x+2a)+1) ... every x replaced by (x+2a)
f(x+2a) = sqrt(2x+4a+1) .... distribute
we can't simplify any further
12000 g would be equal to 12 kg not 1.2 kg so the answer has to be A) greater than.
Answer: A) GREATER THAN
QUESTION 12
The given figure has five unequal sides.
The perimeter is the distance around the figure.
So we add all the lengths of the sides of the rectangle to get,

We regroup the like terms to obtain,

This will simplify to give us,


QUESTION 13
The given figure has two pairs of sides that are equal in length and three unequal sides.
The perimeter can be found by adding all the lengths of the sides of the of the figure.
This will give us

We regroup like terms to obtain,

This finally simplifies to ,
.

QUESTION 14
This plane figure has four sides that are equal to 4j and two sides that are equal to 2h.
We add all the lengths of the sides of the plane figure to get,

This will simplify to give us,
Answer:

Step-by-step explanation:
we know that
The surface area of a sphere is equal to

we have

substitute

