Can someone like do my homeowkr for me? im lazy and it was due yesterday

A slice is made perpendicular to the base of a right rectangular prism as shown.

Eduardwww [97]

Answer:

The correct option is 1. The area of cross section area is 48 mm².

Step-by-step explanation:

From the find it is noticed that the cross section is a rectangle with length 4 mm and width is 12 mm.

The area of a rectangle is the product of its dimensions.

$A=l\times w$

Where, l is length of the rectangle and w is width of the rectangle.

The area of cross section is

$A=4\times 12$

$A=48$

Therefore the area of cross section area is 48 mm². Option 1 is correct.

8 0

3 years ago

Ashton made contributions to a Roth IRA over the course of 32 working years. His contributions averaged $2,400 annually. Ashton

enyata [817]

The formula of the future value of an annuity ordinary is
Fv=pmt [(1+r)^(n)-1)÷r]
Fv future value?
PMT 2400
R 0.08
T 32 years
Fv=2,400×((1+0.08)^(32)−1)÷(0.08)
Fv=322,112.49
Now deducte 28% the tax bracket from the amount we found
annual tax 2,400×0.28 =672 and tax over 32 years is 672×32 =21,504. So the effective value of Ashton's Roth IRA at retirement is 322,112.49−21,504=300,608.49

3 0

3 years ago

To print tickets, a printer chargers a $70 setup fee plus $1.25 per ticket. (a) Write an algebraic expression for the cost of t

ioda

A. 70+1.25t
b. Plug in 650 for t
70+1.25(650)
70+812.5
882.5

Final answer: $882.50

8 0

3 years ago

Find the general solution of the differential equation and check the result by differentiation. (Use C for the constant of integ

atroni [7]

Answer: $y=Ce^(^3^t^{^9}^)$

Step-by-step explanation:

Beginning with the first differential equation:

$\frac{dy}{dt} =27t^8y$

This differential equation is denoted as a separable differential equation due to us having the ability to separate the variables. Divide both sides by 'y' to get:

$\frac{1}{y} \frac{dy}{dt} =27t^8$

Multiply both sides by 'dt' to get:

$\frac{1}{y}dy =27t^8dt$

Integrate both sides. Both sides will produce an integration constant, but I will merge them together into a single integration constant on the right side:

$\int\limits {\frac{1}{y} } \, dy=\int\limits {27t^8} \, dt$

$ln(y)=27(\frac{1}{9} t^9)+C$

$ln(y)=3t^9+C$

We want to cancel the natural log in order to isolate our function 'y'. We can do this by using 'e' since it is the inverse of the natural log:

$e^l^n^(^y^)=e^(^3^t^{^9} ^+^C^)$

$y=e^(^3^t^{^9} ^+^C^)$

We can take out the 'C' of the exponential using a rule of exponents. Addition in an exponent can be broken up into a product of their bases:

$y=e^(^3^t^{^9}^)e^C$

The term e^C is just another constant, so with impunity, I can absorb everything into a single constant:

$y=Ce^(^3^t^{^9}^)$

To check the answer by differentiation, you require the chain rule. Differentiating an exponential gives back the exponential, but you must multiply by the derivative of the inside. We get:

$\frac{d}{dx} (y)=\frac{d}{dx}(Ce^(^3^t^{^9}^))$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*\frac{d}{dx}(3t^9)$

$\frac{dy}{dx} =(Ce^(^3^t^{^9}^))*27t^8$

Now check if the derivative equals the right side of the original differential equation:

$(Ce^(^3^t^{^9}^))*27t^8=27t^8*y(t)$

$Ce^(^3^t^{^9}^)*27t^8=27t^8*Ce^(^3^t^{^9}^)$

QED

I unfortunately do not have enough room for your second question. It is the exact same type of differential equation as the one solved above. The only difference is the fractional exponent, which would make the problem slightly more involved. If you ask your second question again on a different problem, I'd be glad to help you solve it.

7 0

2 years ago

6a^2-[-5a-(9a^2-3a)]-[8+(-19a-8)]

Mamont248 [21]

The answer is 15a^2+21a

5 0

3 years ago