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3 years ago

Factor (x-1)^3 (4x-9) - (16x+9) (x+1)^2 ? Please explain steps, I'm stuck !

Mathematics

1 answer:

Lapatulllka [165]3 years ago

5 0

$(x-1)^3 (4x-9) - (16x+9) (x+1)^2$

$= (x^3-3x^2+3x-1) (4x-9) - (16x+9) (x^2+2x+1)$

$= (4x^4-12x^3+12x^2-4x-9x^3-27x^2-27x+9)-(16x^3+32x^2+16x+9x^2+18x+9)$

$= (4x^4-21x^3+39x^2-31x+9)-16x^3-32x^2-16x-9x^2-18x-9$

$= 4x^4-21x^3+39x^2-31x+9-16x^3-32x^2-16x-9x^2-18x-9$

$= 4x^4-37x^3-2x^2-65x$

$= x(4x^3-37x^2-2x-65)$

hence final factor is $x(4x^3-37x^2-2x-65)$

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Property 1: Every integer is a rational number. It is Theorem 4.3.1.

Property 2: The sum of any two rational numbers is rational. It is Theorem 4.3.2.

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Step-by-step explanation:

* Lets explain how to solve the problem

- Function is a relation where each input has a single output

- The notation of the function is f(x) = y , where x is the input of the

function and y is the out put of the function

- The domain of the function is x and the range of the function is y

* Lets find which table represent a function

# First table:

x y

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0 0

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- In the first table

∵ -3 has only -1

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∵ -2 has only -1

∵ 8 has only 1

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∴ The table represents a function

∴ The 1st table represents a function

- In the second table

x y

-5 -5

0 0

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6 -6

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∴ One x has two values of y

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3 years ago

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