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Juliette [100K]
4 years ago
8

Find the reciprocal 5/6​

Mathematics
2 answers:
denpristay [2]4 years ago
5 0

Answer:

6/5

Step-by-step explanation:

A reciprocal of x is 1/x.

An easier way to find it is to just flip the fraction upside down.

5/6 becomes 6/5.

serious [3.7K]4 years ago
3 0

Answer: 6/5

Step-by-step explanation:

just switch the answer

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If x is 6, then 7x =
Lana71 [14]

I think it's 42 since 7x6=42

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This question has several parts that must be completed sequentially. If you skip a part of the question, you will not receive an
oksano4ka [1.4K]

Answer:

a.) dx3x² + 2

Use the properties of integrals

That's

integral 3x² + integral 2

= 3x^2+1/3 + 2x + c

= 3x³/3 + 2x + c

= x³ + 2x + C

where C is the constant of integration

b.) x³ + 2x

Use the properties of integrals

That's

integral x³ + integral 2x

= x^3+1/4 + 2x^1+1/2

= x⁴/4 + 2x²/2 + c

= x⁴/4 + x² + C

c.) dx6x 5 + 5

Use the properties of integrals

That's

integral 6x^5 + integral 5

= 6x^5+1/6 + 5x

= 6x^6/6 + 5x

= x^6 + 5x + C

d.) x^6 + 5x

integral x^6 + integral 5x

= x^6+1/7 + 5x^1+1/2

= x^7/7 + 5/2x² + C

Hope this helps

8 0
3 years ago
Which two amounts does this statement identify?
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That would be net income (amount made after taxes have been deducted) and hourly wage (amount made per hr at work)
3 0
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Read 2 more answers
Which two values of x are roots of the polynomial below?<br> x2-11x + 15
Alex787 [66]

The two values of roots of the polynomial x^{2}-11 x+15 are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

<u>Solution:</u>

Given, polynomial expression is x^{2}-11 x+15

We have to find the roots of the given expression.

In order to find roots, now let us use quadratic formula.

x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}

Given that x^{2}-11 x+15

Here a = 1, b = -11 and c = 15

On substituting the values we get,

x=\frac{-(-11) \pm \sqrt{(-11)^{2}-4 \times 1 \times 15}}{2 \times 1}

\begin{array}{l}{x=\frac{11 \pm \sqrt{121-60}}{2}} \\\\ {x=\frac{11 \pm \sqrt{61}}{2}} \\\\ {x=\frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}}\end{array}

Hence, the roots of given polynomial are \frac{11+\sqrt{61}}{2} \text { or } \frac{11-\sqrt{61}}{2}

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3 years ago
Using the break apart method to find each product. What is the method for 5X5?
Ipatiy [6.2K]
I believe it is (2+2) × (3+3)
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