the center is at the origin of a coordinate system and the foci are on the y-axis, then the foci are symmetric about the origin.
The hyperbola focus F1 is 46 feet above the vertex of the parabola and the hyperbola focus F2 is 6 ft above the parabola's vertex. Then the distance F1F2 is 46-6=40 ft.
In terms of hyperbola, F1F2=2c, c=20.
The vertex of the hyperba is 2 ft below focus F1, then in terms of hyperbola c-a=2 and a=c-2=18 ft.
Use formula c^2=a^2+b^2c
2
=a
2
+b
2
to find b:
\begin{gathered} (20)^2=(18)^2+b^2,\\ b^2=400-324=76 \end{gathered}
(20)
2
=(18)
2
+b
2
,
b
2
=400−324=76
.
The branches of hyperbola go in y-direction, so the equation of hyperbola is
\dfrac{y^2}{b^2}- \dfrac{x^2}{a^2}=1
b
2
y
2
−
a
2
x
2
=1 .
Substitute a and b:
\dfrac{y^2}{76}- \dfrac{x^2}{324}=1
76
y
2
−
324
x
2
=1 .
Order the numbers from least to greatest. List the numbers as your final answer. 4, 7, -2, 25, 49, 63, 13, -22, 19, -13, 4/4, 34
sp2606 [1]
-22 , -13, -3, -2 , 4/4, 4, 7, 13, 19, 25, 34, 49, 63
68
Explanation:
So to get this answer you need to split it into smaller shapes. We already have the squares so we know that 3*3 is 9 and then we double that because there are two of them.
So, so far we have 18+x
We need to take the middle shape and split it into two trapezoids.
The area for trapezoids is T=(a+b/2)h
So T= (3+7/2)5
T= 5*5=25
And then we would double that because there are two of them so 50 and then fill it in for x
18+50= 68 is the area of the figure.
Answer:
4
Step-by-step explanation:
now gimme a brainliest
