Infinitely many ways!
Suppose you have the fraction 2/d.
<span>Pick </span>any<span> pair of integers a and b where b ≠ 0.</span>
Then 2b-ad is and integer, as is bd so that (2b - ad)/bd is a fraction.
Consider the fractions a/b and (2b - ad)/bd
<span>Their sum is </span>
a/b + (2b-ad)/bd = ad/bd + (2b-ad)/bd = 2b/bd = 2/d - as required.
<span>Since a and b were chosen arbitrarily, there are infinitely many possible answers to the question.</span>
Factor then solve. Exact Form: x = 0 , 7 + √ 97 2 , 7 − √ 97 2 Decimal Form: x = 0 , 8.42442890 … , − 1.42442890 …
Answer:
qn
Step-by-step explanation:
Answer:
The answer is 9996
Step-by-step explanation:
Using the identity (x+a)(x+b) = x ^2 +(a+b)x+ab
Writing 102 as 100+2 and 98 as 100−2
Hence (100+2)(100−2) = 100 ^2 +[2+(−2)]100+(2)(−2)
= 10000+(0)100−4
= 9996
The answer is 9996
