4 years ago

Given right triangle JKL, what is the value of cos(L)?

Mathematics

1 answer:

pogonyaev4 years ago

7 0

Answer:

l its 20

Step-by-step explanation:

20 -10

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A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long

Pie

Answer:

Surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

$S = \frac{1}{2}pl+B$ ...... (1)

Here, p represents the perimeter of the base , $l$ the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid( $l$ ) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = $3 \times (side)$

= $3 \times 20 = 60 inches$

Area of equilateral triangle(B) = $\frac{\sqrt{3} }{4} \times (side)^{2}$

= $\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}$ square inches.

Substitute the above values in equation (1) as shown below:

$S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}$

$S= 390+100\sqrt{3}$ square inches

Hence, the surface area of pyramid with base equilateral triangle is $390+100\sqrt{3}$ square inches.

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