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Evgesh-ka [11]
3 years ago
12

A triangular pyramid has a base shaped like an equilateral triangle. The legs of the equilateral triangle are all 20 inches long

, and the height of the equilateral triangle is 17.3 inches. The pyramid's slant height is 13 inches. What is its surface area?
Mathematics
1 answer:
Pie3 years ago
6 0

Answer:

Surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches

Step-by-step explanation:

Recall the following result:

The total surface area(S) of a regular pyramid is given by,

S = \frac{1}{2}pl+B                                       ...... (1)

Here, p represents the perimeter of the base , l the slant height and B the base area of the pyramid.

From the given information:

Side of equilateral triangle = 20 inches

Slant height of the pyramid(l) = 13 inches.

First find the perimeter and Area of the base pyramid.

Perimeter of equilateral triangle(p) = 3 \times (side)

                                                          = 3 \times 20 = 60 inches

Area of equilateral triangle(B) = \frac{\sqrt{3} }{4} \times (side)^{2}

                                                 =\frac{\sqrt{3} }{4} \times (20)^2 = 100\sqrt{3}  square inches.

Substitute the above values in equation (1) as shown below:

S=\frac{1}{2} \times 60 \times 13+100\sqrt{3}

S= 390+100\sqrt{3} square inches

Hence, the surface area of pyramid with base equilateral triangle is 390+100\sqrt{3} square inches.

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