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2 years ago

How do you do this problem

Mathematics

1 answer:

Ainat [17]2 years ago

4 0

So the problem has no symbols, but we're going to multiply because the fraction on the left is right next to the parentheses.

-5/2 * 1/10x = -5x/20

I put "x" next to the 5 because the "x" counts as part of the numerator. Now that it's 5x over 20 that equals one, I'd first reduce -5x/20 into -x/4, then do

-x/4 * -4 = 1 * -4

To make the "x" side equal one, we have to multiply both sides by -4, to make both sides equal.

x = -4.

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Evaluate the indicated function for f(x) = x2 − 1 and g(x) = x − 2 algebraically. If possible, use a graphing utility to verify

Maru [420]

(F-g)(-2) is the answer

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2 years ago

The vertices of triangle rst are r(–1,–2), s(2,–1), and t(4,2). If δjkl ∼ δrst and the length of kl is units , what is the lengt

NemiM [27]

Answer:

3.16 units

Step-by-step explanation:

It has been given that the triangles JKL and the triangle RST are congruent.

That implies that, the length of the side JK, KL, and JL is equivalent to the length of the sides RS, ST, and RT respectively.

Now, to find the length of JK we need to find the length of the side RS. The coordinates of the points R and S are $(-1,-2)$ and $(2,-1)$ .

The length of the side RS is equal to the distance between point R and S.

RS $=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$= \sqrt{(2-(-1))^2+(-1-(-(-2))^2}$

$=\sqrt{3^2+(-1+2)^2}$

$=\sqrt{9+1}=\sqrt{10}=3.16$

Now that we have the length of the side RS, and the triangles JKL and RST are congruent therefore, the length of the side JK is 3.16 units.

7 0

3 years ago

Read 2 more answers

<img src="https://tex.z-dn.net/?f=%5Csqrt%281-2%29%2B%5Csqrt%281%2B2%29%5C%5C" id="TexFormula1" title="\sqrt(1-2)+\sqrt(1+2)\\"

Kipish [7]

1.4 or square root of 2

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2 years ago

What is times positive 9 times negative 5

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Negative 45 or -45 because different signs with multiplication are always negative

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NASA cameras film a rocket launcher vertically from the launch pad, 3 miles away. When the angle between the camera and the grou

Nimfa-mama [501]

The height of the rocket is found in terms of the angle as
.. h/(3 mi) = tan(θ)
.. h = (3 mi)*tan(θ)

Then the rate of change of height (vertical velocity) is
.. h' = (3 mi)*sec(θ)^2*θ'
.. h' = (3 mi)*4*(1.5 rad/min)
.. h' = 18 mi/min

The rocket's velocity is 18 miles per minute at that moment.

8 0

3 years ago