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weqwewe [10]
3 years ago
8

Triangle L N P has centroid S. Lines are drawn from each point to the midpoint of the opposite side to form line segments N R, L

P, and Q M. The length of line segment N S is 7 x minus 3 and the length of line segment S R is 5 x minus 3. What is the length of segment NS? 1 unit 2 units 4 units 6 units
Mathematics
2 answers:
Irina18 [472]3 years ago
8 0

Answer:

6 units

Step-by-step explanation:

Given: Triangle L N P has centroid S.

NS=7x-3, SR=5x-3

To find: NS

Solution:

Centroid is the point of intersection of the medians of the triangle such that it divides each of the median in ratio 2:1

So,

NS:SR=2:1\\\frac{NS}{SR}=\frac{2}{1}  \\

Put NS=7x-3, SR=5x-3

\frac{7x-3}{5x-3}=\frac{2}{1}\\  7x-3=10x-6\\10x-7x=-3+6\\3x=3\\x=1

Therefore,

NS=7x-3=7(1)-3=4\,\,units\\SR=5x-3=5(1)-3=2\,units

So,

NS=NS+SR=4+2=6\,\,units

Download pptx
Grace [21]3 years ago
7 0

Answer:

The answer is 4

Step-by-step explanation:

It asks for the length of NS not the length of NR

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