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3 years ago

A square window has an area of x2 + 22x + 121 square feet. Find the length of one side of the square.

Mathematics

2 answers:

Aloiza [94]3 years ago

6 0

The answer is A(x+11)

d1i1m1o1n [39]3 years ago

4 0

x + 11 ft

Step-by-step explanation:

x² + 22x + 121 ft² = area of square

x² + 11x + 11x + 121 ft² = side²

x(x + 11) + 11(x + 11) ft² = side²

(x + 11)(x + 11) ft² = side²

(x + 11)² ft² = side²

x + 11 ft = side²

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Yuki888 [10]

Answer: H

Step-by-step explanation:

We can see this rectangular prism will have side lengths of 5, 3, 7.

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3 years ago

Consider the equation below.

Korvikt [17]

Answer:

Equation in square form:

$y=3(x+5)^2-4$

Extreme value:

$(h,k)=(-5,-4)$

Step-by-step explanation:

We are given

$y=3x^2+30x+71$

we can complete square

$y=3(x^2+10x)+71$

we can use formula

$a^2+2ab+b^2=(a+b)^2$

$y=3(x^2+2\times x\times 5)+71$

now, we can add and subtract 5^2

$y=3(x^2+2\times x\times 5+5^2-5^2)+71$

$y=3(x^2+2\times x\times 5+5^2)-3\times 5^2+71$

$y=3(x+5)^2-75+71$

So, we get equation as

$y=3(x+5)^2-4$

Extreme values:

we know that this parabola

and vertex of parabola always at extreme values

so, we can compare it with

$y=a(x-h)^2+k$

where

vertex=(h,k)

now, we can compare and find h and k

$y=3(x+5)^2-4$

we get

h=-5

k=-4

so, extreme value of this equation is

$(h,k)=(-5,-4)$

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3 years ago

Read 2 more answers

Can anyone help me with part C?

finlep [7]

Answer:430

Step-by-step explanation:78 times 3 is 430

3 0

2 years ago