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brilliants [131]
2 years ago
6

Hello! Can I get this confirmed, please? I already graphed the line.

Mathematics
2 answers:
KATRIN_1 [288]2 years ago
7 0

Yup it's correct :) good job!

Sveta_85 [38]2 years ago
7 0

Nice job!!

Yes, you have it prefect!!


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At 9 AM you have run 2 miles. At 9:24 AM you have run 5 miles. What is your running rate in minutes per mile
rosijanka [135]
I think it's 8 b/c 24 minutes divided by 3 miles is 8 minutes per mile.
4 0
3 years ago
Which Relation is a Function Please Answer ASAP
earnstyle [38]

Answer:

A

Step-by-step explanation:

Every input (x value) can have only ONE ouput (y value) to be a function, y- values can be repeated but x- values cannot

Hope that helps

3 0
3 years ago
(HURRY) Janet is mixing a 15% glucose solution with a 35% glucose solution. This mixture produces 35 liters of a 19% glucose sol
Arturiano [62]

Answer:

c. 28 liters

Step-by-step explanation:

Given tha tJanet is mixing a 15% glucose solution with a 35% glucose solution. This mixture produces 35 liters of a 19% glucose solution. Now we need to find about how many liters of the 15% solution is Januet using in the mixture.

Let the number of liters of the 15% solution is Januet using in the mixture = x

Let the number of liters of the 35% solution is Januet using in the mixture = y

Then we get equations:

x+y=35...(i)

and

(15% of x) + (35% of y) = 19% of 35.

or

0.15x+0.35y=0.19(35)

15x+35y=19(35)

3x+7y=19(7)

3x+7y=133 ...(ii)

solve (i) for x

x+y=35

x=35-y...(iii)

Plug (iii) into (ii)

3x+7y=133

3(35-y)+7y=133

105-3y+7y=133

105+4y=133

4y=133-105

4y=28

y=28/4

y=7

plug y=7 into (iii)

x=35-y=35-7=28

Hence final answer is c. 28 liters

5 0
3 years ago
Read 2 more answers
PLEASE ANSWER IN 50 MIN I WILL MARK BRAINLIEST
hammer [34]

Answer:

174lbs

Step-by-step explanation:

I'm not positive but its my best shot

8 0
2 years ago
Can someone pls explain this to me. I thought I understood it but everything I type in is incorrect!:(
kakasveta [241]
Notice the graph, the domain is just the horizontal area "used up" over the x-axis, so, the graph goees from \bf -\cfrac{5x}{2}\quad to\quad \cfrac{5x}{2}\implies domain\implies \left[-\cfrac{5x}{2}\ ,\   \cfrac{5x}{2}\right]

the range is just, the vertical area "used up" over the y-axis, so, the graph goes to 2 and down to -2, thus    \bf range\implies [2\ ,\ -2]
4 0
3 years ago
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