Question

Solve for x enter your answer in interval notation using grouping symbols x²+2x<8

Answer 1

X^2 + 2x < 8 x^2 + 2x - 8 < 0 (x + 4)(x - 2) < 0 ,, {x + 4 < 0 and x - 2 > 0} or {x + 4 > 0 ,,and x - 2 < 0} ,, {x < -4 and x > 2} or {x > -4 and x < 2},, Discard x < -4 and x > 2 because it has no solutions, leaving just x > -4 and x < 2 ,, -4 < x < 2