Are you supposed to do all the ones in the quotations?
Answer:

And replacing we got:
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And then the final term would be:
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Step-by-step explanation:
For this case we have the following expression:

And we can use the binomial theorem given by:

And for this case we want to find the fourth term and using the formula we have:

And replacing we got:

And then the final term would be:

The answer is D
0 is not less than or equal to -4, and in the second equation, 0 is greater than -1
To find f(1), substitute 1 for x.
f(1) = (3(1)+7)²
f(1) = (3+7)²
f(1) = 10²
f(1) = 100
We are to form the combination of 6 objects taken 2 at a time. This can be expressed as 6C2

This means, there can be 15 different combinations of 2 members that can sit in the front row.
So, the answer to this question is option A