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iren2701 [21]
3 years ago
5

How many songs are we supposed to listen to in lesson number 2?

SAT
1 answer:
alexira [117]3 years ago
5 0
I don’t sing
Sorry
Plz forgive me
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In what type of plate boundary did volcanoes form?u
Artist 52 [7]

Answer:

convergant plate boundary

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3 years ago
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What is the value of 67th percentile in a standard normal distribution?
Vikki [24]

Let Z be a random variable following the standard normal distribution with mean µ = 0 and standard deviation σ = 1.

The 67th percentile of the distribution is the value z that separates the bottom 67% of the distribution from the top 100% - 67% = 33%. In terms of probability, we have

Pr[Z ≤ z] = 0.67

Use the inverse CDF for the normal distribution (or lookup z scores in a table) to find

z = ɸ⁻¹(0.67) ≈ 0.4399

where ɸ(z) is the CDF for the normal distribution.

8 0
2 years ago
Suppose y is inversely proportional to x. If y = –8 when x = –2, find y when x = 32
Annette [7]

Answer: 1/2

Explanation:

When y is inversely proportional to x. This implies that:

y = k/x

If y = –8 when x = –2, then the constant of proportionality will be;

y = k/x

-8 = k/-2

k = (-8 × -2)

k = 16

when x = 32, the value of y will be:

y = k/x

y = 16/32

y = 1/2

5 0
2 years ago
For the galvanic (voltaic) cell fe(s) + mn²⁺(aq) ⟶ fe²⁺(aq) + mn(s) (e° = 0.77 v at 25°c), what is [fe²⁺] if [mn²⁺] = 0.050 m an
Nuetrik [128]

The concentration of Iron in the galvanic (voltaic) cell Fe(s) + Mn²⁺(aq) ⟶ Fe²⁺(aq) + Mn(s) is 0.02297 M.

<h3>What is the Nernst Equation?</h3>

The Nernst equation enables us to identify the cell potential(voltage) in presence of non-standard conditions in a galvanic cell. It can be expressed by using the formula:

\mathbf{E_{cell} = E_o - \dfrac{0.059}{n} \times log \dfrac{[Fe^+]}{[Mn^{2+}]}}

where;

  • n = Number of electrons = 2
  • \mathbf{E_o} = Initial voltage = 0.77 V
  • \mathbf{E_{cell}} = Cell voltage = 0.78 V
  • \mathbf{[Mn^{2+}]} = Manganese concentration = 0.050 M

Replacing the values into the above equation, we have:

\mathbf{0.78 = 0.77 - \dfrac{0.059}{2} \times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{0.78 -0.77= -0.0296\times log \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{log^{-1} (-0.3378) = \dfrac{[Fe^{2+}]}{[0.050]}}

\mathbf{Fe^{2+} = (0.4594\times 0.050 )\ M}

\mathbf{Fe^{2+} =0.02297 \ M }

Learn more about using the Nernst equation here:

brainly.com/question/24258023

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2 years ago
B b b b b g g g. Gg g. B b b b b g g ghshussuhsbus
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dujsb eiiwbeio sisayg euskwow

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