I'm not completely sure but this is what I would do.
evaluate <span>(1/ 4)^x - 1 </span>as is. But change the (1 /2)^2x to (2/4)^2x. This way both fractions have the same denominator and in this sense, the same base. The 2/4 base still evaluates into 1/2 so nothing, mathematically, is being broken here.
Answer:
56
Step-by-step explanation:
Complete question:
Z varies jointly with x and y , x=2 and y=2, z=7. Find z when x=4 and y=8 using joint variation . (I need the problem worked out step by step)
If z varies jointly with x, and y, this is expressed as;
z = kxy
If z=7 when x= 2, y= 2
7 = k(2)(2)
7 = 4k
k = 7/4
To get z when x= 4 and y = 8
z = kxy
z =7/4 (4)(8)
z = 7*8
z = 56
Hence the value of z is 56
For perpendicular lines, m1m2 = -1 or m2 = -1/m1; where m1 and m2 are the slopes of the lines.
Here line 1 is 2x - y - 7 = 0
y = 2x - 7; Hence m1 = 2
m2 = -1/2
Required equation y - y1 = m2(x - x1)
y - (-1) = -1/2(x - 4)
y + 1 = -1/2x + 2
y = -1/2x + 2 - 1
y = -1/2x + 1
0/20 cause they said suppose so it didn't happen. idk cause i am not in college i am in middle school
