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2 years ago

PLS HALP ASAP =w=!!!! (will mark u teh brainliest if you explain the problem properly and clearly, 20 pts uwu!)

Mathematics

1 answer:

Oksanka [162]2 years ago

7 0

N = 3 i = 2
2 x 2 = 4
3 x 3 = 9
4 + 9 = 13
13 = area

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A farmer sells four of his farm products Maize, Potatoes, carrots and tomatoes in each of 2 towns into classes of 3 customers. C

nordsb [41]

Answer:

Step-by-step explanation:

7 0

2 years ago

A grocery delivery service has 22 members. Each member pays monthly dues of $12.80

slava [35]

Answer:

Step-by-step explanation:

If 9 members paid on the first day, this means they did not pay on the third day

The remaining people (everyone but the 9) paid on the third day

Therefore we must subtract to find out how many members paid on the third day

22 - 9 = 13

Each of the 13 members paid $12.80 which means we must multiply

13 × 12.80 = 166.40

In total, the grocery store collected $166.40 on the third day of the month

3 0

3 years ago

Read 2 more answers

In a G.P the difference between the 1st and 5th term is 150, and the difference between the

liubo4ka [24]

Answer:

Either $\displaystyle \frac{-1522}{\sqrt{41}}$ (approximately $-238$ ) or $\displaystyle \frac{1522}{\sqrt{41}}$ (approximately $238$ .)

Step-by-step explanation:

Let $a$ denote the first term of this geometric series, and let $r$ denote the common ratio of this geometric series.

The first five terms of this series would be:

$a$ ,
$a\cdot r$ ,
$a \cdot r^2$ ,
$a \cdot r^3$ ,
$a \cdot r^4$ .

First equation:

$a\, r^4 - a = 150$ .

Second equation:

$a\, r^3 - a\, r = 48$ .

Rewrite and simplify the first equation.

$\begin{aligned}& a\, r^4 - a \\ &= a\, \left(r^4 - 1\right)\\ &= a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) \end{aligned}$ .

Therefore, the first equation becomes:

$a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right) = 150$ ..

Similarly, rewrite and simplify the second equation:

$\begin{aligned}&a\, r^3 - a\, r\\ &= a\, \left( r^3 - r\right) \\ &= a\, r\, \left(r^2 - 1\right) \end{aligned}$ .

Therefore, the second equation becomes:

$a\, r\, \left(r^2 - 1\right) = 48$ .

Take the quotient between these two equations:

$\begin{aligned}\frac{a\, \left(r^2 - 1\right) \, \left(r^2 + 1\right)}{a\cdot r\, \left(r^2 - 1\right)} = \frac{150}{48}\end{aligned}$ .

Simplify and solve for $r$ :

$\displaystyle \frac{r^2+ 1}{r} = \frac{25}{8}$ .

$8\, r^2 - 25\, r + 8 = 0$ .

Either $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ or $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ .

Assume that $\displaystyle r = \frac{25 - 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = -\frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= -\frac{1522\sqrt{41}}{41} \approx -238\end{aligned}$ .

Similarly, assume that $\displaystyle r = \frac{25 + 3\, \sqrt{41}}{16}$ . Substitute back to either of the two original equations to show that $\displaystyle a = \frac{497\, \sqrt{41}}{41} - 75$ .

Calculate the sum of the first five terms:

$\begin{aligned} &a + a\cdot r + a\cdot r^2 + a\cdot r^3 + a \cdot r^4\\ &= \frac{1522\sqrt{41}}{41} \approx 238\end{aligned}$ .

4 0

2 years ago

What is the median of the data?<br>30,29,16,11,16,20,21,12,13,15,15,23,30

tia_tia [17]

Answer:

Step-by-step explanation:

ascending order:11,12,13,15,15,16,16,20,21,23,29,30,30

number of terms =13

median=[(n+1)/2] th term

=[(13+1)/2] th term

=[14/2] th tem

=7th term

=16

7 0

3 years ago

A hardware store sells light bulbs in different quantities. the graph shows the cost of various quantities. according to the gra

geniusboy [140]

step 1

find the equation of the line

where

x-------> numbers of light bulbs

y-------> the total cost in $

let

A (0,0) B (10,18)

slope m=18/10-----> m=1.8

step 2

with m=1.8 and the point A (0,0)

y-y1=m*(x-x1)------> y=1.8x

step 3

for x=1

y=1.8*1------> y=$1.8

therefore

the answer is

the cost of a single light bulb is $1.8

4 0

3 years ago