If you want to calculate 18/4.52, you can do this using the following steps:
18/4.52 = 18 / 4 52/100 = 18 / 452/100 = 18 * 100/452 = 1800/452 = 450/113 = 3.98
The correct result is 3.98.
Answer:
1/16 of a mile left to walk to reach the end of the road
Step-by-step explanation:
The total distance to be walked = 15/16 miles
already walked= 7/8 miles = 14/16 miles
15/16 - 14/16 = 1/16 miles
Hoi!
The correct answer would be "Daryl received two 3's as scores on his paper from the readers, but Sheila received two 6's."
When placing a number in a sentence before an S, it is to always have an apostrophe. Along with this, this is the only sentence that uses the correct form of "readers", since in this sentence, "readers" is being used as a plural noun, not a possessive noun.
Possessive nouns contain an apostrophe to show that something belongs to someone else.
Ex: That cat is her's.
The possessive noun is "her's" because it's showing that she is the owner of the cat.
As for plural tense, it speaks for more than one person or object.
Ex: The cats scrambled up the tree.
The plural noun is "cats" because it's referring to more than one cat.
:)
Answer:
A) 3.5
16 shovels full
Step-by-step explanation:
9x + 13 = 17x - 15
8x = 28
x = 3.5
20 + 5x = 32 + 4.25x
0.75x = 12
x = 16
<h3>
Answer:</h3>
(2x + 1)(x + 3)
<h3>
Step-by-step explanation:</h3>
It is probably easier to try the answer choices than to try to factor the expression yourself.
(2x + 2)(x + 1) = 2x² +4x +2
(2x + 3)(x + 1) = 2x² +5x +3
(2x + 1)(x + 3) = 2x² +7x +3 . . . . . correct choice
_____
<em>Constructed solution</em>
If you want to factor this yourself, you can look for factors of "ac" that add to give "b". That is, you want factors of 2·3 = 6 that add up to give 7. You don't have to look very far.
... 6 = 1·6 = 2·3 . . . . . . the first factor pair adds to give 7
Now, rewrite the x term using the sum of these numbers.
... 2x² +(1 +6)x +3
... 2x +x +6x +3 . . . . eliminate parentheses
... (2x +x) +(6x +3) . . . . group pairs of terms
... x(2x +1) +3(2x +1) . . . . factor each pair
... (x +3)(2x +1) . . . . . . matches the last selection
