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ludmilkaskok [199]
3 years ago
10

PLS HALP ASAP =w=!!!! (will mark u teh brainliest if you explain the problem properly and clearly, 20 pts uwu!)

Mathematics
1 answer:
Oksanka [162]3 years ago
7 0
N = 3 i = 2
2 x 2 = 4
3 x 3 = 9
4 + 9 = 13
13 = area
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What is 21935483.87 rounded to the nearest million
elixir [45]
21,935,483.87 rounded to the nearest million is 22,000,000.00
5 0
3 years ago
What is 12 dollars an hour
Reptile [31]

Answer:

I think you are missing something from the question, but if you were to find out how much you would get paid for a certain amount of hours from $12 per hour, then the formula would be:

Step-by-step explanation:

Let h = no. of hours worked

$12 * h

8 0
3 years ago
Reduce the following fraction 25/55<br><br><br> Pls help quickly
Lina20 [59]

Answer:

5/11

Step-by-step explanation:

5 0
3 years ago
A pizza pan is removed at 9:00 PM from an oven whose temperature is fixed at 450°F into a room that is a constant 70°F. After 5​
gladu [14]

Answer:

A) It will get to a temperature of 125°F at 9:19 PM

B) It will get to a temperature of 150°F at 9:16 PM

C) as time passes temperature approaches the initial temperature of 450°F

Step-by-step explanation:

We are given;

Initial temperature; T_i = 450°F

Room temperature; T_r = 70°F

From Newton's law of cooling, temperature after time (t) is given as;

T(t) = T_r + (T_i - T_r)e^(-kt)

Where k is cooling rate and t is time after the initial temperature.

Now, we are told that After 5​ minutes, the temperature is 300°F.

Thus;

300 = 70 + (450 - 70)e^(-5k)

300 - 70 = 380e^(-5k)

230/380 = e^(-5k)

e^(-5k) = 0.6053

-5k = In 0.6053

-5k = -0.502

k = 0.502/5

k = 0.1004 /min

A) Thus, at temperature of 125°F, we can find the time from;

125 = 70 + (450 - 70)e^(-0.1004t)

125 - 70 = 380e^(-0.1004t)

55/380 = e^(-0.1004t)

In (55/380) = -0.1004t

-0.1004t = -1.9328

t = 1.9328/0.1018

t ≈ 19 minutes

Thus, it will get to a temperature of 125°F at 9:19 PM

B) Thus, at temperature of 150°F, we can find the time from;

150 = 70 + (450 - 70)e^(-0.1004t)

150 - 70 = 380e^(-0.1004t)

80/380 = e^(-0.1004t)

In (80/380) = -0.1004t

-0.1004t = -1.5581

t = 1.5581/0.1004

t ≈ 16 minutes.

Thus, it will get to a temperature of 150°F at 9:16 PM

C) As time passes which means as it approaches to infinity, it means that e^(-kt) gets to 1.

Thus,we have;

T(t) = T_r + (T_i - T_r)

T_r will cancel out to give;

T(t) = T_i

Thus, as time passes temperature approaches the initial temperature of 450°F

6 0
3 years ago
"a u.S. 1-cent coin (a penny) has a diameter of 19 mm and a thickness of 1.5 mm". Assume the coin is made of pure copper, whose
choli [55]

<u>the question is </u> Calculate the value of the copper in the coin

Step 1

Find the volume of the coin

we know that

the volume of a cylinder is equal to

V=\pi r^{2}h

where

r is the radius of the coin

h is the thickness of the coin

in this problem we have

Diameter=19 mm=1.9 cm

r=D/2------> r=1.9/2=0.95 cm

h=1.5 mm=0.15 cm

substitute the values in the formula

V=\pi*0.95^{2}*0.15=0.425\ cm^{3}

Step 2

<u>Find the mass of copper in the coin</u>

we know that

the density is equal to

Density=mass/volume

Solve for the mass

mass=Density*volume

we have

Density=8.9\ gr/cm^{3}\\Volume=0.425\ cm^{3}

substitute in the formula

mass=8.9*0.425=3.785\ gr

Step 3

<u>Find the cost</u>

we know that

the market price of the copper is $2.15 per pound

1 pound=453.592 grams

convert gram to pounds

3.785 gr=3.785/453.592=0.0083 pounds

0.0083*$2.15=$0.018=$0.02

therefore

<u>the answer is</u>

$0.02

3 0
3 years ago
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