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3 years ago

Help with 2 questions please!

Mathematics

1 answer:

Semmy [17]3 years ago

5 0

I believe the first one is 0.8 not for sure though

You might be interested in

Is -8.43 a integer whole number or a rational number ?

s2008m [1.1K]

Answer:

rational number

Step-by-step explanation:

A whole number would be just 8. Nothing behind it.

5 0

3 years ago

How do rigid motions affect a given figure?

12345 [234]

Can you post a picture about the question

3 0

3 years ago

Ok I rlly need help with this question it’s rlly hard for me there’s a picture to show —> helppp

Whitepunk [10]

Answer:

x=20; vertical angles theorem

Step-by-step explanation:

hi! we can use the vertical angles theorem for this. vertical angles are congruent to each other, meaning they are the same amount of degrees. so, we can set 2x+10 and 50 equal to each other.

2x+10=50

2x=40

x=20

x=20 because of the vertical angles theorem.

8 0

3 years ago

In a MBS first year class, there are three sections each including 20 students. In the first section, there are 10 boys and 10 g

KIM [24]

Answer:

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

Step-by-step explanation:

The selection is from a sample without replacement, so we use the hypergeometric distribution to solve this question.

Hypergeometric distribution:

The probability of x sucesses is given by the following formula:

$P(X = x) = h(x,N,n,k) = \frac{C_{k,x}*C_{N-k,n-x}}{C_{N,n}}$

In which:

x is the number of sucesses.

N is the size of the population.

n is the size of the sample.

k is the total number of desired outcomes.

Combinations formula:

$C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

All girls from the first group:

20 students, so $N = 20$

10 girls, so $k = 10$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_1 = P(X = 5) = h(5,20,5,10) = \frac{C_{10,5}*C_{10,5}}{C_{20,5}} = 0.0163$

All girls from the second group:

20 students, so $N = 20$

5 girls, so $k = 5$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_2 = P(X = 5) = h(5,20,5,5) = \frac{C_{5,5}*C_{15,5}}{C_{20,5}} = 0.00006$

All girls from the third group:

20 students, so $N = 20$

8 girls, so $k = 8$

5 students will be selected, so $n = 5$

We want all of them to be girls, so we find P(X = 5).

$P_3 = P(X = 5) = h(5,20,5,8) = \frac{C_{8,5}*C_{12,5}}{C_{20,5}} = 0.0036$

All 15 students are girls:

Groups are independent, so we multiply the probabilities:

$P = P_1*P_2*P_3 = 0.0163*0.00006*0.0036 = 3.52 \times 10^{-9}$

$3.52 \times 10^{-9} = 3.52 \times 10^{-7}\%$ probability that all the 15 students selected are girls

7 0

3 years ago

Find the volume of each rectangular prism or cylinder with the given dimensions. Round to the nearest hundredth, if necessary.

Doss [256]

The answer is A. 60.16 ft3

4 0

3 years ago