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Alex_Xolod [135]
2 years ago
13

I really need help asap! ty!

Mathematics
1 answer:
Keith_Richards [23]2 years ago
8 0

The length of AL in the triangle is 12cm.

<h3>How to calculate the value?</h3>

From the information given, angle C = 90° and BAC is given as 2ABC.

In this case, the length of angle BC is given as 24cm. Therefore, the length of AL will be:

= 24/2

= 12..

Therefore, AL = 12cm

Learn more about triangles on:

brainly.com/question/1058720

#SPJ1

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Fantom [35]
Answer: A) 60°
The inscribed angle is half the measure of the arc.
3 0
3 years ago
Eric jogged 31/4 miles on monday 5 5/8 miles on tuesday and 8 miles on wensday .suppose he continues the pattern for the remaind
Troyanec [42]
The is increasing by 2 3/8
So the answer is 12 3/4 miles on Friday

Hope this helps :)
3 0
3 years ago
A movie theater charges $15 for standard viewing, $20 for 3D viewing, and $35 for Dinner and a
Ludmilka [50]

The quantity of each type of seats sold are as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

According to the question,there are four times as many 3D, x seats as Dinner and a Movie, y seats.

That is, x = 4y

Also, total seats

= (x) + (y) + (z) = 3000...….............eqn(1)

Also, If the theater brings in $53,000 when tickets to all 3000 seats are sold.

  • 20x + 35y + 15z = 53000...........eqn(2)

By substituting 4y for x in equations 1 and 2; we have;

<em>5y + z = 3000</em>..…........eqn(3) and

<em>115y + 15z = 53000</em>.........eqn(4)

By solving equations 3 and 4 simultaneously; we have;

y = 200 and z = 2000

and since x = 4y

x = 800

The quantity of each type of seats sold is as follows:

  • Standard viewing = 2000

  • 3D seats = 800

  • Movie and a dinner seat = 200

Read more:

brainly.com/question/12413726

5 0
3 years ago
Town A and town B calculated the number of dogs in each town based on the average number of dogs per neighborhood. The graph bel
Inga [223]
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5 0
3 years ago
Assume that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles
OverLord2011 [107]

Answer:

Final answer is approx 6.644 years.

Step-by-step explanation:

Given that a company sold 5.75 million motorcycles and 3.5 million cars in the year 2010. The growth in the sale of motorcycles is 16% every year and that of cars is 25% every year.

So we can use growth formula:

A=P\left(1+r\right)^t

Then we get equation for motorcycles and cars as:

A=5.75\left(1+0.16\right)^t

A=3.5\left(1+0.25\right)^t

Now we need to find about when the sale of cars will be more than the sale of motorcycles. So we get:

3.5\left(1+0.25\right)^t>5.75\left(1+0.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

3.5\left(1.25\right)^t>5.75\left(1.16\right)^t

\frac{\left(1.25\right)^t}{\left(1.16\right)^t}>\frac{5.75}{3.5}

\left(\frac{1.25}{1.16}\right)^t>1.64285714286

t\cdot\ln\left(\frac{1.25}{1.16}\right)>\ln\left(1.64285714286\right)

t>\frac{\ln\left(1.64285714286\right)}{\ln\left(\frac{1.25}{1.16}\right)}

t>6.6436473051

Hence final answer is approx 6.644 years.

7 0
3 years ago
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