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3 years ago

Translate and simply: subtract 18 from -11

Mathematics

1 answer:

navik [9.2K]3 years ago

4 0

Answer: -29

Subtract 18 FROM -11.
That means that 18 would go after -11.

-11 - 18 = -29

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Simplify the expression below:

kifflom [539]

Answer:

C. -7x^2 - 28

Step-by-step explanation:

Firstly simplify the bracket before doing anything;

4x(3x - 7) = 12x^2 - 28x

then go back to the question and substitute the expression(12x^2 - 28x) on the bracket and then work out the question;

12x^2 - 28x -19x^2...then group the values with the same exponent of x,

(12x^2 - 19x^2) - 28x

; -7x^2 - 28x

6 0

3 years ago

Seattle, wa and san francisco, ca lie on the same longitudinal line. san francisco is at 38° latitude and seattle is at 47° lati

Varvara68 [4.7K]

Step 1.

Calculate measure of angle α:

$47^o-38^o=9^o$

Step 2.

Calculate what fraction of the angle 360° is the angle α:

$\dfrac{9^o}{360^o}=\dfrac{1}{40}$

Step 3.

Calculate the circumference of the Earth (circle):

$C=2\pi r\to C=2\pi\cdot4000=8000\pi\ mi$

Step 4.

The length of arc is equal 1/40 of the circumference:

$\dfrac{1}{40}C=\dfrac{1}{40}\cdot8000\pi=200\pi\ mi$

$\pi\approx3.14\to\dfrac{1}{40}C\approx200\cdot3.14=628\ mi$

<h3>Answer: A) 628 miles</h3>

8 0

3 years ago

Write an algebraic equation for each question below and then solve the equation.

Aneli [31]

Answer:

$number = x \\ number \: decreaed \: by \: 8 = > x - 8 = 26 \\ x - 8 = 26 \\ x = 8 + 26 \\ x = 34 \\ thank \: you$

3 0

3 years ago

Read 2 more answers

A box of colored pencils contains exactly 6 red pencils. The probability of choosing a red pencil from the box is 2/7 how many o

Colt1911 [192]

2/7=6/x
2x=42
x=21
the answer is c

8 0

3 years ago

According to a Los Angeles Times study of more than 1 million medical dispatches from to , the response time for medical aid var

-BARSIC- [3]

Answer:

A)Mean :10.65

Median =10.7

Mode : 10.7

B)Range = 3.5

Standard deviation :0.89916

C)The response time of 8.3 minutes should be considered an outlier in comparison to the other response times

Step-by-step explanation:

Data : 11.8 ,10.3, 10.7, 10.6, 11.5, 8.3, 10.5, 10.9, 10.7, 11.2

$Mean = \frac{\text{Sum of all observations}}{\text{No. of observations}}\\Mean = \frac{11.8 +10.3+ 10.7+ 10.6+ 11.5+ 8.3+ 10.5+ 10.9+ 10.7+ 11.2}{10}$

Mean = 10.65

Median: The mid value of the data

Data in ascending order

8.3

10.3

10.5

10.6

10.7

10.9

11.2

11.5

11.8

n=10(even)

$Median = \frac{(\frac{n}{2})\text{th term}+(\frac{n}{2}+1)\text{th term}}{2}\\Median = \frac{(\frac{10}{2})\text{th term}+(\frac{10}{2}+1)\text{th term}}{2}\\Median = \frac{10.7+10.7}{2}\\Median = 10.7$

Mode : the most occurring frequency

10.7 is occurring twice while others are occurring once

So, Mode is 10.7

B) Range = Maximum - Minimum=11.8-8.3=3.5

Standard deviation : $\sqrt{\frac{\sum(x-\bar{x})^2}{n}}$

Standard deviation : $\sqrt{\frac{(11.8-10.65)^2+(10.3-10.65)^2+......+(10.9-10.65)^2+(10.7-10.65)^2+(11.2-10.65)^2}{10}}$

Standard deviation :0.89916

8.3

,10.3

,10.5

,10.6

,10.7

,10.9

,11.2

,11.5

,11.8

For Q1 ( Median of lower quartile )

8.3

,10.3

,10.5

,10.6

,10.7

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=10.5$

For Q3( Median of Upper quartile )

10.7

,10.9

,11.2

,11.5

,11.8

$Median = \frac{n+1}{2}\text{th term} =\frac{5+1}{2}=3 \text{rd term}=11.2$

IQR = Q3-Q1=11.2-10.5=0.7

Range :(Q1-1.5IQR, Q3-1.5IQR)

Range : $(10.5-1.5 \times 0.7, 11.2-1.5 \times 0.7)$

Range :(9.45, 10.15)

8.3 does not lie in this interval

So, the response time of 8.3 minutes should be considered an outlier in comparison to the other response times

3 0

3 years ago