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3 years ago

One of the tents you look at has a base measuring 3 metres long and 250 centimetres wide what is the area of the tent

Mathematics

1 answer:

ozzi3 years ago

5 0

3 +250= 253 take 253 dived it by 3 ,subtract 4 =80.3

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PLEASE HELP ASAP!!! I NEED CORRECT ANSWERS ONLY PLEASE!!! I NEED TO FINISH THESE QUESTIONS BEFORE MIDNIGHT TONIGHT.

Lina20 [59]

Yo sup??

we can solve this question by applying trigonometric ratios

cos59=CB/CD

CD=CB/cos59

=7.8

Hope this helps.

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2 years ago

Please answer A B C or D:

ss7ja [257]

C I think that's it idk I might be wrong sorry if I am

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2 years ago

30 POINTS AVAILABLE

kherson [118]

Answer:

$\large\boxed{(x-2)^2+(y-1)^2=34}$

Step-by-step explanation:

The equation of a circle in standard form:

$(x-h)^2+(y-k)^2=r^2$

(h, k) - center

r - radius

We have the endpoints of the diameter: (-1, 6) and (5, -4).

Midpoint of diameter is a center of a circle.

The formula of a midpoint:

$\left(\dfrac{x_1+x_2}{2};\ \dfrac{y_1+y_2}{2}\right)$

Substitute:

$h=\dfrac{-1+5}{2}=\dfrac{4}{2}=2\\\\k=\dfrac{6+(-4)}{2}=\dfrac{2}{2}=1$

The center is in (2, 1).

The radius length is equal to the distance between the center of the circle and the endpoint of the diameter.

The formula of a distance between two points:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Substitute the coordinates of the points (2, 1) and (5, -4):

$r=\sqrt{(5-2)^2+(-4-1)^2}=\sqrt{3^2+(-5)^2}=\sqrt{9+25}=\sqrt{34}$

Finally we have:

$(x-2)^2+(y-1)^2=(\sqrt{34})^2$

3 0

3 years ago

What is the area of sector?

Shtirlitz [24]

Answer:

Step-by-step explanation:

since 90 degrees is 1/4 of a circle, the area of the sector is 5²pi/4 = 25/4pi = 19.63

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3 years ago

A coin will be flipped three times. The result of each flip is either heads (H) or tails (T). The outcome HTH represents the fir

Yuki888 [10]

The answer is 4/7
Welcome x

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3 years ago