One of the tents you look at has a base measuring 3 metres long and 250 centimetres wide what is the area of the tent
1 answer:
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Shift the graph of the function y = x², 5 units down /look at the picture #1/.
/look at the picture #2/ - your answer
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<span>
it consists of a rectangle, dimensions L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2
</span>then, you have one half of the area of the circle that has diameter R = 3ft - radius will be r = 1.5ft the area of that half will be:
Ac = r^2
/ 2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2
= 7.065 ft^2/ 2
= 3.5325ft^2
A = Ar + Ac
A = 12ft^2 + 3.5325ft^2
A = 15.5325ft^2
<span>At the rate of $2 per square foot, the cost will be:
$ 15.5325*2 = 31.07 </span>
<span>
it consists of a rectangle, dimensions L = 4ft and W = 3ft = Ar = 4ft x 3ft = 12 ft^2
</span>then, you have one half of the area of the circle that has diameter R = 3ft - radius will be r = 1.5ft the area of that half will be:
Ac = r^2
= (1.5 ft)^2 x 3.14 / 2
= 2.25 ft^2 x 3.4/2
= 7.065 ft^2/ 2
= 3.5325ft^2
A = Ar + Ac
A = 12ft^2 + 3.5325ft^2
A = 15.5325ft^2
<span>At the rate of $2 per square foot, the cost will be:
$ 15.5325*2 = 31.07 </span>