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AleksandrR [38]

4 years ago

14

If 2i + (x + yi) = 6, what is x + yi?

1 answer:

velikii [3]4 years ago

6 0

X+yi = 6-2i
hope it helps!!

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If, triangle ABC, the measure of angle B is greater than 90 degrees, and AB=BC, what is a possible measure for angle C in degree

sasho [114]

Answer:

A

Step-by-step explanation:

Let us start with B = 90

That would mean that each of the other 2 angles must add to 90 which makes each of them 45.

But the question doesn't allow that. B has to be greater than 90 which means that the other two angles must be less that 45 each.

the only answer that does that is A

8 0

3 years ago

97% of steel is made of iron. If there are 500 lbs of steel, approximately how many pounds are iron?

I am Lyosha [343]

Answer:

485 Pounds of Iron

Step-by-step explanation:

500 x 97% or 500 x 0.97 = 485.

6 0

3 years ago

Two distinct number cubes, one red and one blue, are rolled together. Each number cube has sides numbered 1 through 6.

cestrela7 [59]

Answer:

$P(E_1 or E_2) = \frac{7}{12}$

Step-by-step explanation:

Given

Two cubes of side 1 - 6

Required

Probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5

First, the sample space needs to be listed;

Let $C_r$ represent the Red cube

$C_b$ represent the Blue cube

S represent the sample space

$C_r = (1,2,3,4,5,6)\\C_b = (1,2,3,4,5,6)\\S = (2,3,4,5,6,7,3,4,5,6,7,8,4,5,6,7,8,9,5,6,7,8,9,10,6,7,8,9,10,11,7,8,9,10,11,12)$ S is gotten by getting the sum of $C_r$ and $C_b$

$n(S) = 36$

<em>Calculating the Probability</em>

Let $E_1$ represent the event that an outcome is an odd sum

$E_1 = (3,5,7,3,5,7,5,7,9,5,7,9,7,9,11,7,9,11)$

$n(E_1) = 18$

$P(E_1) = \frac{n(E_1)}{n(S)}$

$P(E_1) = \frac{18}{36}$

Let $E_2$ represent the event that an outcome is a multiple of 5

$E_2 = (5,5,5,5,10,10,10)$

$n(E_2) = 7$

$P(E_2) = \frac{n(E_2)}{n(S)}$

$P(E_2) = \frac{7}{36}$

Let $E_3$ represent the event that an outcome is an odd sum and a multiple of 5

$E_3 = E_1 and E_2$

$E_3 = (5,5,5,5)$

$n(E_3) = 4$

$P(E_3) = \frac{n(E_3)}{n(S)}$

$P(E_3) = \frac{4}{36}$

Calculating $P(E_1 or E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_1 and E_2)$

$P(E_1 or E_2) = P(E_1) + P(E_2) - P(E_3)$

$P(E_1 or E_2) = \frac{18}{36} + \frac{7}{36} - \frac{4}{36}$

$P(E_1 or E_2) = \frac{18 + 7 - 4}{36}$

$P(E_1 or E_2) = \frac{21}{36}$

$P(E_1 or E_2) = \frac{7}{12}$

Hence, the probability that the outcome of the roll is an odd sum or a sum that is a multiple of 5 is $\frac{7}{12}$

6 0

3 years ago

Y = 3x - 1 Let x = 6. The ordered pair is (6,_).

kirill115 [55]

Answer:

Step-by-step explanation:

y = 2x - 1

x = 6

y = 3*6 - 1

y = 18 - 1

y = 17

(6,17)

4 0

3 years ago

The sophomore class holds a car wash to raise money. A local merchant donates all of the supplies. A wash cost $5 per car and $6

Taya2010 [7]

Use any letter "x" is the usual one but since you have 2 you can use 2 different ones.

5 0

3 years ago