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3 years ago

11

The sophomore class holds a car wash to raise money. A local merchant donates all of the supplies. A wash cost $5 per car and $6

.50 per van or truck......how do i define a variable for the number of cars and a different variable for the number of vans or trucks

1 answer:

Taya2010 [7]3 years ago

5 0

Use any letter "x" is the usual one but since you have 2 you can use 2 different ones.

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[15 Points] Solve for x.<br> <img src="https://tex.z-dn.net/?f=45x%2B34%3D24x%2B16" id="TexFormula1" title="45x+34=24x+16" alt="

sergiy2304 [10]

Answer:

6/7

Step-by-step explanation:

45x+34=24x+16

collect like terms, we now have;

45x-24x=16-34

21x=-18

X=18/21

X=6/7

8 0

3 years ago

Morgan, Dakota and Taylor showed their work solving the equation 7x+5x+1=73. Identify the student with the invalid first step an

antoniya [11.8K]

Answer:

Step-by-step explanation:

Given the equation solved by Morgan, Dakota and Taylor expressed as 7x+5x+1=73, to get the value of x, the valid steps are as shown;

7x+5x+1=73

take the sum of 7x and 5x

12x+ 1 = 73

subtract 1 from both sides

12x+1-1 = 73-1

12x = 72

Divide both sides by 12

12x/12 = 72/12

x = 6

Based on the calculation above, the students with invalid first step is Dakota.

<em>Dakota added 5x with 1 to get 6x which is an invalid step because 1 is not attached to a variable x. A function cannot be added to a constant hence making his first step invalid.</em>

8 0

3 years ago

Read 2 more answers

A golfball is hit from the ground with an initial velocity of 200 ft/sec. The horizontal distance that the golfball will travel,

algol13

Answer:

The golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

Step-by-step explanation:

The formula from the maximum distance of a projectile with initial height h=0, is:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}$

Where $v_i$ is the initial velocity.

In the closed interval method, the first step is to find the values of the function in the critical points in the interval which is $[0, \pi/2]$ . The critical points of the function are those who make $d'(\theta)=0$ :

$d(\theta)=\frac{v_i^2\sin(2\theta)}{g}\\d'(\theta)=\frac{v_i^2\cos(2\theta)}{g}*(2)\\d'(\theta)=\frac{2v_i^2\cos(2\theta)}{g}$

$d'(\theta)=0\\\frac{2v_i^2\cos(2\theta)}{g}=0\\\cos(2\theta)=0\\2\theta=\pi/2,3\pi/2,5\pi/2,...\\\theta=\pi/4,3\pi/4,5\pi/4,...$

The critical value inside the interval is $\pi/4$ .

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\d(\pi/4)=\frac{v_i^2sin(2(\pi/4))}{g}\\d(\pi/4)=\frac{v_i^2sin(\pi/2)}{g}\\d(\pi/4)=\frac{v_i^2(1)}{g}\\d(\pi/4)=\frac{(200)^2}{32}\\d(\pi/4)=\frac{40000}{32}\\d(\pi/4)=1250ft$

The second step is to find the values of the function at the endpoints of the interval:

$d(\theta)=\frac{v_i^2sin(2\theta)}{g}\\\theta=0\\d(0)=\frac{v_i^2sin(2(0))}{g}\\d(0)=\frac{v_i^2(0)}{g}=0ft\\\theta=\pi/2\\d(\pi/2)=\frac{v_i^2sin(2(\pi/2))}{g}\\d(\pi/2)=\frac{v_i^2sin(\pi)}{g}\\d(\pi/2)=\frac{v_i^2(0)}{g}=0ft$

The biggest value of f is gived by $\pi/4$ , therefore $\pi/4$ is the absolute maximum.

In the context of the problem, the golfball launched with an initial velocity of 200ft/s will travel the maximum possible distance which is 1250 ft when it is hit at an angle of $\pi/4$ .

4 0

3 years ago

Please help me with this

Eva8 [605]

Answer:

128

Step-by-step explanation:

they are parralel

6 0

2 years ago

Read 2 more answers

wo mechanics worked on a car. The first mechanic charged $95 per hour, and the second mechanic charged $75per hour. The mechanic

Elenna [48]

5 hours and 25 minutes I think (Im not sure)

8 0

2 years ago

Read 2 more answers