We are given the following variables:
μ = the sample mean = 152 pounds
σ = the standard deviation = 26 pounds
x = the sample value we want to test = 180 pounds
n = the sample size = unknown
MOE = margin of error = 4% = 0.04
Confidence level = 96%
The first thing we can do is to find for the value of z
using the formula:
z = (x – μ) / σ
z = (180 – 152) / 26
z = 1.0769 = 1.08
Since we are looking for the people who weigh more than
180 pounds, therefore this is a right tailed z test. The p value is:
p = 0.1401
Then we can use the formula below to solve for n:
n = z^2 * p * (1 – p) / (MOE)^2
n = 1.08^2 * 0.1401 * (1 – 0.1401) / (0.04)^2
n = 87.82 = 88
Therefore around 88 people must be surveyed.
Answer:
-8/3 or -2.66666 or -2 2/3
Step-by-step explanation:
Move constant (+9) to the right side and change its sign (25 - 9)
Then subtract those numbers (=16)
Divide both sides by -6
The coterminal angle to (33/10)π on the interval [0, 2π] is (13/10)π
<h3>
How to find the coterminal angle?</h3>
For any given angle A, the family of coterminal angles is defined by:
B = A + n*2π
Where n can be any integer number different than zero.
In this case, we have:
A = (33/10)π
Now we want to get a coterminal angle to A on the interval [0, 2π]. Then we need to find the value of n such that:
B = (33/10)π + n*2π
Is on the wanted interval.
If we take n = -1, then we get:
B = (33/10)π - 2π = (33/10)π - (20/10)π = (13/10)π
Which is in fact in the wanted interval.
The coterminal angle to (33/10)π on the interval [0, 2π] is (13/10)π
If you want to learn more about coterminal angles:
brainly.com/question/3286526
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