Answer:
3/10 is smaller than 4/5. so no there are not
Step-by-step explanation:
pls mark branliest
The symbol "<=" without quotes means "less than or equal to"
-6x + 2y <= 42
-6x + 2y + 6x <= 42 + 6x ... Add 6x to both sides
2y <= 6x + 42
2y/2 <= 6x/2 + 42/2 ... divide every term by 2
y <= 3x + 21
So the answer is choice D
Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since
<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0
and
<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0
it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.
