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xenn [34]
3 years ago
9

Use the IVT to prove that one solution to

{3} +x-5=0" alt="x^{3} +x-5=0" align="absmiddle" class="latex-formula"> is between x=1 and x=2.
Please show work and if your answer makes no sense I will report. Thanks
Mathematics
1 answer:
Dafna11 [192]3 years ago
7 0

Let <em>f(x)</em> = <em>x</em>³ + <em>x</em> - 5. <em>f(x)</em> is a polynomial so it's continuous everywhere on its domain (all real numbers). Since

<em>f</em> (1) = 1³ + 1 - 5 = -3 < 0

and

<em>f</em> (2) = 2³ + 2 - 5 = 5 > 0

it follows by the intermediate value theorem that there at least one number <em>x</em> = <em>c</em> between 1 and 2 for which <em>f(c)</em> = 0.

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zubka84 [21]

Answer:

3x+85= 21

or, 3x= 85- 21

or, 3x= 64

or,x= 64/3

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Step-by-step explanation:

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8 0
3 years ago
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artcher [175]
1 + (-5/8) = 3/8

Explanation: If the coffee wasn’t drank it would’ve been at fraction 1 (or 100%)

Since he drank 5/8 of it. The coffee left is now 1-(5/8)

But since the question has asked to give the equation in addition format. Put a plus sign in between the two.

Therefore,
1 + (-5/8)

Solve it,
= 1-(5/8)
= (8-5)/8
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Hence the equation is:

1 + (-5/8) = 3/8.
8 0
3 years ago
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Which area model represents 0.4 x 0.7 = 0.28?​
sammy [17]

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Step-by-step explanation:

8 0
2 years ago
Is <img src="https://tex.z-dn.net/?f=1-2x%5E%7B2%7D" id="TexFormula1" title="1-2x^{2}" alt="1-2x^{2}" align="absmiddle" class="l
Schach [20]

Answer:

standard form for a quadratic expression

Step-by-step explanation:

This is a quadratic expression.  If you want this expression in standard form, write the terms in descending order of powers of x:  -2x^2 + 1.

This   -2x^2 + 1   has not yet been factored.

-2x^2 + 1 is in standard form.

7 0
2 years ago
If EM=11, AM=16, and CF=27, what are the lengths of the following sides?
tensa zangetsu [6.8K]

Answer:

18

Step-by-step explanation:

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