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inysia [295]
3 years ago
6

Brown spotting of the teeth in humans is caused by a dominant X-linked gene. If a man with normal teeth marries a woman with bro

wn teeth who had a father with normal teeth, then _______ of their daughters will have brown teeth.ave%20two%20Barr%20bodies.
a 100%
b 50%
c 25%

Biology
1 answer:
nata0808 [166]3 years ago
7 0

Answer:

25%

Explanation:

The female with brown teeth had a father with normal teeth. Since normal teeth is a recessive trait, the father would have been homozygous recessive for the trait and would have transmitted one recessive allele to the female. Therefore, the female is heterozygous dominant for brown teeth.

Let's assume that the allele for brown teeth is X^B while the one for normal teeth is X^b. The genotype of heterozygous dominant female would be X^BX^b and that of the male with normal teeth would be X^bY.

A cross between X^BX^b and X^bY gives progeny in following phenotype ratio= 1/4 daughter with brown teeth: 1/4 daughter with normal teeth: 1/4 son with brown teeth: 1/4 son with normal teeth. Therefore, the probability of having a daughter with brown teeth is = 25%

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For a particular species of wolf, 55% are female, 20% hunt in medium-sized packs, and 15% are both female and hunt in medium-siz
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*Given
Percent of the wolves which are female - 55%
Percent of the wolves which hunt 
     in medium-sized packs                      - 20%
Percent of the wolves which are both
     female and hunt in medium-sized
     packs                                                  - 15%


*Solution

<u>Assuming that there is a total of one hundred wolves in the species, </u>

1. Since percent (%) means "per 100" or "for every 100" then, 

a. The number of female wolves is

    (55 female wolves / 100 wolves) * 100 wolves total = 55 female wolves

b. The number of wolves that hunt in medium-sized packs is

    (20 wolves / 100 wolves) * 100 wolves total = 20 wolves

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c. The number of female wolves that hunt in medium-sized packs is

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2. Because there is a total of 55 female wolves in the species, and 15 of these wolves hunt in medium-sized packs, then the number of female wolves that do not hunt in medium-sized packs is, 
 
    55 female wolves total - 15 female wolves hunting  = 40 female wolves not
                                                in medium-sized packs         hunting in medium
                                                                                              sized packs

3. To find the proportion, we can express the answer in terms of percent (%) or in fraction, which is usually how proportions are expressed. 

For every 100 wolves, there are 40 female wolves that do not hunt in medium-sized packs. This can be expressed as a proportion of 
 
                                       <span> <u> 40  </u>
</span>                                        100

and simplified by dividing both the numerator and denominator by 10, we get,

                                     <span><u> 40/10  </u>
</span>                                     100/10

                                       <span><u>  4   </u>
</span>                                        10

When this is expressed in percent, we multiply the fraction or proportion by 100% to get, 

                                       <span><u>  4   </u>   x    100%     = 40%
</span>                                        10

Thus, the proportion of female wolves that do not hunt in medium sized packs is 4/10 or 0.4. When expressed as percent, this is 40%. 
  
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