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Eduardwww [97]
4 years ago
10

In a poll conducted by a survey firm, 82% of respondents said that their jobs were sometimes or always stressful. Eleven workers

are chosen at random for the Binomial experiment. What is the probability that more than 9 of them find their jobs stressful
Mathematics
1 answer:
ollegr [7]4 years ago
4 0

Answer:

P(X >9) = P(X=10) +P(X=11)

And we can find the individual probabilities with the mas function adn we got:

P(X=10)=(11C10)(0.82)^{10} (1-0.82)^{11-10}=0.272  

P(X=11)=(11C11)(0.82)^{11} (1-0.82)^{11-11}=0.113  

And replacing we got:

P(X>9) =0.272 +0.113= 0.385

Step-by-step explanation:

Let X the random variable of interest "number of workers who find their jobs stressful", on this case we now that:  

X \sim Binom(n=11, p=0.82)  

The probability mass function for the Binomial distribution is given as:  

P(X)=(nCx)(p)^x (1-p)^{n-x}  

Where (nCx) means combinatory and it's given by this formula:  

nCx=\frac{n!}{(n-x)! x!}  

We want to find the following probability:

P(X >9) = P(X=10) +P(X=11)

And we can find the individual probabilities with the mas function adn we got:

P(X=10)=(11C10)(0.82)^{10} (1-0.82)^{11-10}=0.272  

P(X=11)=(11C11)(0.82)^{11} (1-0.82)^{11-11}=0.113  

And replacing we got:

P(X>9) =0.272 +0.113= 0.385

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