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pychu [463]
3 years ago
13

A junk box in your room contains a dozen old batteries, five of which are totally dead. You start picking batteries one at a tim

e and testing them. Find the probability of each outcome.
(a) The first two you choose are both good.
(b) At least one of the first three works.
(c) The first four you pick all work.
(d) You have to pick five batteries in order to find one that works.
Mathematics
1 answer:
Brums [2.3K]3 years ago
4 0

Okay if I am correct this is on probability, right?

So you basically have to put 5 over 12, 5/12 because five of the doen batteries are dead. Then, divide 5 over 12, and you'll get .416, and then divide 4 over 16, and you will get get 0.25 which reduces down to 1/4 which is your answer. So, your answer is (c) because the answer says the first four you pick will all work.

Hope this gives you a good deal of help! Rate as brainliest if it was the best answer. Thanks!

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3 questions in 1
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Answer:

1. D. 20, 30, and 50

2. A. 86

3. B. 94

Step-by-step explanation:

1. To find the outliers of the data set, we need to determine the Q1, Q3, and IQR.

The Q1 is the middle data in the lower part (first 10 data values) of the data set (while the Q3 is the middle data of the upper part (the last 10 data values) the data set.

Since it is an even data set, therefore, we would look for the average of the 2 middle values in each half of the data set.

Thus:

Q1 = (85 + 87)/2 = 86

Q3 = (93 + 95)/2 = 94

IQR = Q3 - Q1 = 94 - 86

IQR = 8

Outliers in the data set are data values below the lower limit or above the upper limit.

Let's find the lower and upper limit.

Lower limit = Q1 - 1.5(IQR) = 86 - 1.5(8) = 74

The data values below the lower limit (74) are 20, 30, and 50

Let's see if we have any data value above the upper limit.

Upper limit = Q3 + 1.5(IQR) = 94 + 1.5(8) = 106

No data value is above 106.

Therefore, the only outliers of the data set are:

D. 20, 30, and 50

2. See explanation on how to we found the Q1 of the given data set as explained earlier in question 1 above.

Thus:

Q1 = (85 + 87)/2 = 86

3. Q3 = (93 + 95)/2 = 94

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2 years ago
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Step-by-step explanation:

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