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Svet_ta [14]
3 years ago
9

Which expressions is equivalent to 2r+(t+r)

Mathematics
1 answer:
azamat3 years ago
8 0

Answer:

t+3r

Step-by-step explanation:

This is a one step solution

All you do is add like terms

In this case the only like terms are the varibles r

2r+(t+r)

so if you add all of the rs together there would be 3rs

So the rest of the problem would continue as normal while bringing the 3r to the end

t+3r

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A solution of salt and water contain 75 grams of water per 150 millimeters of the solution. If 1 mole of water weight 16 grams, how many moles of water would be present in 30 mil liter of the solution.
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3 years ago
Algebraically determine if the relation y = x3 − 4x is symmetric with respect to the x-axis, y-axis, the origin or has no symmet
Gala2k [10]
\bf y=x^3-4x
\\\\\\
\textit{check for y-axis symmetry}\\\\
\stackrel{x=-x}{y=(-x)^3-4(-x)}\implies y=(-x)(-x)(-x)+4x\implies \boxed{y=-x^3+4x}
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\textit{checking for x-axis symmetry}\\\\
\stackrel{y=-y}{(-y)=x^3-4x}\implies -y=x^3-4x\implies \boxed{y=-x^3+4x}
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\textit{checking for origin symmetry}\\\\
\stackrel{x=-x\qquad y=-y}{(-y)=(-x)^3-4(-x)}\implies -y=(-x)(-x)(-x)+4x
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-y=-x^3+4x\implies y=\cfrac{-x^3+4x}{-1}\implies \boxed{y=x^3-4x}\quad \checkmark

notice, if you replace x = -x and y = -y accordingly for each test for symmetry, if the resulting function, is equal to the original function, then it has that type of symmetry.
7 0
3 years ago
Find the area of the circle shown.
BigorU [14]

Answer:

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4 0
2 years ago
Divide a number by 7, and then subtract 4 from the quotient
Ronch [10]
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3 0
3 years ago
Read 2 more answers
A car travels 15 km in 13 minutes. What is its average speed in km/h?
Bogdan [553]

Answer:

  • 69.45 km/h

Step-by-step explanation:

  • Speed = Distance/Time
  • => Speed = 15 km ÷ 13/60
  • => Speed = 15 km ÷ 0.216
  • => Speed = 15 km/0.216
  • => Speed = 15 x 4.63/0.216 x 4.63
  • => Speed = 69.45 km/1 h (Approximate)

<u>Conclusion:</u>

  • Therefore, the speed is 69.45 km/h (Approximate)

Hoped this helped.

3 0
3 years ago
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